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Can you explain the concept behind the problem? Can you explain where the numbers came from? And if it's possible can you provide another example. Can you show the calculations in great detail please

Can you explain the concept behind the problem? Can you explain where the numbers came from? And if it's possible can you provide another example. Can you show the calculations in great detail please

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you explain the concept behind the problem?

Can you explain where the numbers came from? And if it's possible can you provide another example.
Can you show the calculations in great detail please

Calculate the mass percentage of NaCl in a solution containing 1.50 g sodium chloride in 50.0 g of water. Solution Thus: Total mass of solution = 1.50 g + 50.5 g = 51.5 g % NaCl = 1.50g x 100 = 2.91 % NaCl 51.5 g Practice Exercise 3b A commercial bleaching solution contains 3.62 mass % sodium hypochlorite. What is the mass of NaOCI in a 2.5-kg bottle of bleach? Solution This is a relatively easy question. The quoted percentage means that for every 100 g c solution, 3.62 g are the solute, sodium hypochlorite. You can set up a proportion, or note that the percentage is constant: 3.62% = 0.0362 Thus: kg NaOCI = 0.0362 x 2.5 kg = 0.0905 kg NaOCI = 90.5 g NaOCI -OR- 3.62 g 100.0 g X 2500.0 g x = 90.5 g NaOCI
Transcribed Image Text:Calculate the mass percentage of NaCl in a solution containing 1.50 g sodium chloride in 50.0 g of water. Solution Thus: Total mass of solution = 1.50 g + 50.5 g = 51.5 g % NaCl = 1.50g x 100 = 2.91 % NaCl 51.5 g Practice Exercise 3b A commercial bleaching solution contains 3.62 mass % sodium hypochlorite. What is the mass of NaOCI in a 2.5-kg bottle of bleach? Solution This is a relatively easy question. The quoted percentage means that for every 100 g c solution, 3.62 g are the solute, sodium hypochlorite. You can set up a proportion, or note that the percentage is constant: 3.62% = 0.0362 Thus: kg NaOCI = 0.0362 x 2.5 kg = 0.0905 kg NaOCI = 90.5 g NaOCI -OR- 3.62 g 100.0 g X 2500.0 g x = 90.5 g NaOCI
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