can you check if the following code is correct for the following question and can you show me the screen shot of the out put. Thank you so much ; include the irvine libraryINCLUDE Irvine32.inc;Data section declare all the variables.data source BYTE "This is the source string",0 target BYTE SIZEOF source DUP('#');Code section.code main PROC ;assign value o to esi mov esi,0 ;find the length of the source ;subtract with 2 and assign to edi mov edi,LENGTHOF source - 2 ;find the number of bytes used source ;assign to ecx mov ecx,SIZEOF source ;iterate a loop L1: ;get the value of source at index esi ;and move into register al. mov al,source[esi] ;move the value of al into target array ;at index edi. mov target[edi],al ;increment the value of esi inc esi ;decrement the value of edi. dec edi loop L1 ;get the address value of the target ;into edx. mov edx, OFFSET target ;print the string call WriteString exitmain ENDPEND main Programming Exercise 2 :-COPY A STRING IN REVERSE ORDERWrite a program with a loop and indirect addressing that copies a string from source to target, reversing the character order in the process. You MUST use theexact data block, memory allocation and initialization, as shown in the followings for testing - for showing that your code would not over-write the originaldata at the head(4 '$'s) middle(4 '%'s) and tail(4 '^'s):BYTE 4 DUP('$')source BYTE "This is the source string",0BYTE 4 DUP ('%')SIZEOFSIZEOF source DUP ('#')sourcetarget BYTEBYTE 4 DUP('^')Hint: Should Not copy the null character, O, at the end of the source string to the front of the target string. And, finish writing the target string by writing thenull character, O, to the last byte - replacing the last '#' there.In the output of the program, both the source and target(reversed) strings should be shown, by calling the Irvine peripheral procedure(s). Use the following testcode to display the Whole Data Bank:mov edx, OFFSET source-4call WriteStringmov edx, OFFSET target-4call WriteStringmov edx, OFFSET target+SIZEOF target ; display the 4 "^"call WriteString; display the 4 "$" and source string; display the 4 "%" and target stringIMPORTANT: for this exercise, NOT allowable to use any one of these directives: .IF, .ELSE, .ELSEIF, .WHILE, .REPEAT, etc

can you check if the following code is correct for the following question and can you show me the screen shot of the out put. Thank you so much ; include the irvine library INCLUDE Irvine32.inc ;Data section declare all the variables .data source BYTE "This is the source string",0 target BYTE SIZEOF source DUP('#') ;Code section .code main PROC ;assign value o to esi mov esi,0 ;find the length of the source ;subtract with 2 and assign to edi mov edi,LENGTHOF source - 2 ;find the number of bytes used source ;assign to ecx mov ecx,SIZEOF source ;iterate a loop L1: ;get the value of source at index esi ;and move into register al. mov al,source[esi] ;move the value of al into target array ;at index edi. mov target[edi],al ;increment the value of esi inc esi ;decrement the value of edi. dec edi loop L1 ;get the address value of the target ;into edx. mov edx, OFFSET target ;print the string call WriteString exit main ENDP END main

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Question

can you check if the following code is correct for the following question and can you show me the screen shot of the out put. Thank you so much

; include the irvine library
INCLUDE Irvine32.inc

;Data section declare all the variables
.data
source BYTE "This is the source string",0
target BYTE SIZEOF source DUP('#')

;Code section
.code
main PROC
   ;assign value o to esi
    mov esi,0
   ;find the length of the source
   ;subtract with 2 and assign to edi
   mov edi,LENGTHOF source - 2
   ;find the number of bytes used source
   ;assign to ecx
   mov ecx,SIZEOF source
   ;iterate a loop
    L1:
   ;get the value of source at index esi
   ;and move into register al.
    mov al,source[esi]
   ;move the value of al into target array
   ;at index edi.
    mov target[edi],al
   ;increment the value of esi
     inc esi
   ;decrement the value of edi.
     dec edi
     loop L1
   ;get the address value of the target
   ;into edx.
    mov edx, OFFSET target
   ;print the string
    call WriteString
exit
main ENDP
END main

Programming Exercise 2 :-
COPY A STRING IN REVERSE ORDER
Write a program with a loop and indirect addressing that copies a string from source to target, reversing the character order in the process. You MUST use the
exact data block, memory allocation and initialization, as shown in the followings for testing - for showing that your code would not over-write the original
data at the head(4 '$'s) middle(4 '%'s) and tail(4 '^'s):
BYTE 4 DUP('$')
source BYTE "This is the source string",0
BYTE 4 DUP ('%')
SIZEOF
SIZEOF source DUP ('#')
source
target BYTE
BYTE 4 DUP('^')
Hint: Should Not copy the null character, O, at the end of the source string to the front of the target string. And, finish writing the target string by writing the
null character, O, to the last byte - replacing the last '#' there.
In the output of the program, both the source and target(reversed) strings should be shown, by calling the Irvine peripheral procedure(s). Use the following test
code to display the Whole Data Bank:
mov edx, OFFSET source-4
call WriteString
mov edx, OFFSET target-4
call WriteString
mov edx, OFFSET target+SIZEOF target ; display the 4 "^"
call WriteString
; display the 4 "$" and source string
; display the 4 "%" and target string
IMPORTANT: for this exercise, NOT allowable to use any one of these directives: .IF, .ELSE, .ELSEIF, .WHILE, .REPEAT, etc

Expert Solution

Step 1: Define assembly language

In the Assembly language, to copy a string in reverse order by using any of the assembly language, you will need to use a loop to iterate over the characters in the string and copy them into a new string in reverse order. You will also need to use a couple of registers to keep track of the current index in both the source and destination strings.

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.