Can someone fix my code i just get a empty black screen when I run A system is set up to take raw grading information from the console and calculate a consolidatedgrade. The information comes in as a single line with first name, last name, homework grade ( a totaout of 20 ), lab grade (a total out of 50 ), exam grade average, and a letter ( upper or lower )indicating Audit, Passfail, or Grade.Sample :Mary Poppins 17 28 87 gA program should be written that takes the input data and calculates a consolidated FINAL gradebased upon 10% Homework, 20 % Lab , and 70% Exams.The output should be formatted in columns of 7, no decimals. first initial lastname - normalizedhomework-normalized lab-exam-final grade For a pass/fail student output should indicate onlyPass or Fail . For an audit output should say not gradeable Winclude using nanespace std;int main() {cout « "enter first name : ";cout « "enter last name :";// Declaring respective variablesstring firstNane, lastName;double homeworkGrade, labGrade, examAvg;char letter;// Reading input from consolecin >> firstNane >> lastName;cin >> homeworkGrade >> 1labGrade >> exanAvg;cin >> letter;// Now calculating gradedouble homeworkAvg = (homeworkGrade/20.0) * 10.0;double labavg = (labGrade/50.0) * 20.8;double examMark = (examAvg/180.0) * 78.8;double totalAvg = homeworkAvg + labAvg + exanMark;char grade;string res = "Pass";if (totalAvg > 85)grade = 'A';else if (totalAvg >= 79 && totalAvg <= 85)grade - "B';else if (totalAvg >= 70 &8 totalAvg <= 78)grade = 'C';else if (totalAvg >= 60 &8 totalAvg <= 69)grade = 'D';else if (totalAvg >= 50 &8 totalAvg <= 59)grade = 'E';else {grade - "F';res = "Fail"; // neans candidate is fail// Now showing formatted outputscout « "Output:-" « endl;cout « firstName <« " " <« lastName <« " "« (int)homeworkAvg <<* « (int)labAvg « " " « (int)exanMark «" ";// Now showing grade or pass/fail based on letterif (letter == 'A' || letter == 'a')cout « "not gradable";else if (letter == "P' || letter == "p')cout « res;else if (letter == "G' || letter == 'g')cout « grade;cout <« endl;return e;

Answered: Can someone fix my code i just get a…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

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Can someone fix my code i just get a empty black screen when I run

A system is set up to take raw grading information from the console and calculate a consolidated
grade. The information comes in as a single line with first name, last name, homework grade ( a tota
out of 20 ), lab grade (a total out of 50 ), exam grade average, and a letter ( upper or lower )
indicating Audit, Passfail, or Grade.
Sample :
Mary Poppins 17 28 87 g
A program should be written that takes the input data and calculates a consolidated FINAL grade
based upon 10% Homework, 20 % Lab , and 70% Exams.
The output should be formatted in columns of 7, no decimals. first initial lastname - normalized
homework-normalized lab-exam-final grade For a pass/fail student output should indicate only
Pass or Fail . For an audit output should say not gradeable

Winclude <iostrean>
using nanespace std;
int main() {
cout « "enter first name : ";
cout « "enter last name :";
// Declaring respective variables
string firstNane, lastName;
double homeworkGrade, labGrade, examAvg;
char letter;
// Reading input from console
cin >> firstNane >> lastName;
cin >> homeworkGrade >> 1labGrade >> exanAvg;
cin >> letter;
// Now calculating grade
double homeworkAvg = (homeworkGrade/20.0) * 10.0;
double labavg = (labGrade/50.0) * 20.8;
double examMark = (examAvg/180.0) * 78.8;
double totalAvg = homeworkAvg + labAvg + exanMark;
char grade;
string res = "Pass";
if (totalAvg > 85)
grade = 'A';
else if (totalAvg >= 79 && totalAvg <= 85)
grade - "B';
else if (totalAvg >= 70 &8 totalAvg <= 78)
grade = 'C';
else if (totalAvg >= 60 &8 totalAvg <= 69)
grade = 'D';
else if (totalAvg >= 50 &8 totalAvg <= 59)
grade = 'E';
else {
grade - "F';
res = "Fail"; // neans candidate is fail
// Now showing formatted outputs
cout « "Output:-" « endl;
cout « firstName <« " " <« lastName <« " "
« (int)homeworkAvg <<
* « (int)labAvg « " " « (int)exanMark «" ";
// Now showing grade or pass/fail based on letter
if (letter == 'A' || letter == 'a')
cout « "not gradable";
else if (letter == "P' || letter == "p')
cout « res;
else if (letter == "G' || letter == 'g')
cout « grade;
cout <« endl;
return e;

Expert Solution

Step 1

Code:

#include <iostream>
using namespace std;

int main() {

// Declaring respective variables

string firstName, lastName;
double homeworkGrade, labGrade, examAvg;
char letter;
cout<<"enter first name and last name and homework grade , labgrade , exam grade average and a letter : "<<endl;
// Reading input from console

cin >> firstName >> lastName;
cin >> homeworkGrade >> labGrade >> examAvg;
cin >> letter;

// Now calculating grade

double homeworkAvg = (homeworkGrade / 20.0) * 10.0;
double labAvg = (labGrade / 50.0) * 20.0;
double examMark = (examAvg / 100.0) * 70.0;

double totalAvg = homeworkAvg + labAvg + examMark;

char grade;
string res = "Pass";

if(totalAvg > 85)
grade = 'A';
else if(totalAvg >= 79 && totalAvg <= 85)
grade = 'B';
else if(totalAvg >= 70 && totalAvg <= 78)
grade = 'C';
else if(totalAvg >= 60 && totalAvg <= 69)
grade = 'D';
else if(totalAvg >= 50 && totalAvg <= 59)
grade = 'E';
else {
grade = 'F';
res = "Fail"; // means candidate is fail
}

// Now showing formatted outputs

cout << "Output:-" << endl;
cout << firstName << " " << lastName << " "
<< (int)homeworkAvg << " " << (int)labAvg << " " << (int)examMark << " ";

// Now showing grade or pass/fail based on letter

if(letter == 'A' || letter == 'a')
cout << "not gradable";
else if(letter == 'P' || letter == 'p')
cout << res;
else if(letter == 'G' || letter == 'g')
cout << grade;

cout << endl;

return 0;
}

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