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Can someone explain why do the signs change on the final answer? I just need an explanation because I got the answer here. I`m confused because the answer was negative at first then it becomes positive.a

Can someone explain why do the signs change on the final answer? I just need an explanation because I got the answer here. I`m confused because the answer was negative at first then it becomes positive.a

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can someone explain why do the signs change on the final answer? I just need an explanation because I got the answer here. I`m confused because the answer was negative at first then it becomes positive.a

3. Using Momentum Consnvation, * mi4 tm2Mz :. 3x4) + 8x(-2) = (3+8) v V= -0-364m/s] → 0:344m/3 towards left. - (m, tm2) V Momenkum consuvation, Using midl, tmqlle = m,v, tone Vz 3x4 + 8x(m2) - 3(-1) + 8 (V) :. V2 = -0.128 m/s) → 6.125 m/s towands ut.
Transcribed Image Text:3. Using Momentum Consnvation, * mi4 tm2Mz :. 3x4) + 8x(-2) = (3+8) v V= -0-364m/s] → 0:344m/3 towards left. - (m, tm2) V Momenkum consuvation, Using midl, tmqlle = m,v, tone Vz 3x4 + 8x(m2) - 3(-1) + 8 (V) :. V2 = -0.128 m/s) → 6.125 m/s towands ut.
Given data Mass of 1st ball (ml) = 200 g Mass of 2nd ball(m2) = 400 g Speed of 1st ball (u) = 30 cm/s Speed of 2nd ball be v Speed of both ball after collision is zero(motionless) Solution Conservation of momentum Initial momentum = final momentum mlu + m2v =0 200 x 30 + 400 x v=0 v= - 15 cm/s negative shows that 2nd ball moves to leftward v= 15 cm/s
Transcribed Image Text:Given data Mass of 1st ball (ml) = 200 g Mass of 2nd ball(m2) = 400 g Speed of 1st ball (u) = 30 cm/s Speed of 2nd ball be v Speed of both ball after collision is zero(motionless) Solution Conservation of momentum Initial momentum = final momentum mlu + m2v =0 200 x 30 + 400 x v=0 v= - 15 cm/s negative shows that 2nd ball moves to leftward v= 15 cm/s
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