Can someone explain the step by step process of this solution like how it happened. In step 2, why there is 1000 on equation (v1^2-v2^2/ 2 x 1000) and gz1/ 1000. Is it some sort of unit convertion? if yes, then in what unit?Help me with the definition of this terms too;- Z1- Z2- ΔUThank you! STEP2usiry SFEE ,Energy In =Energy outP,v,++32,+Prz(9Z, +Q-WAリ=(P,-B2X IDDD1000162-2702 9.81X32DU=(600x0.37 - 100x0.62)+2メ50D(000-gr 135Du= - 20.00g K5)kg-sign fnadicaredecremeny- OtA internalene9Ang.- fnternal energy dereyebyOption (O is correct. STEP1given-work done= 135F5e, = 0:37 mkg V2-0.62 m)P,こ600と Pa,P2=100KPgV2= 270m)sZ,=32M,Heat lossinureeseTo be find - check specifie internal eierTerdeereare.eneroyordeerease,and chenges ofinternaleneroy A .

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Answered: Can someone explain the step by step…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Can someone explain the step by step process of this solution like how it happened. In step 2, why there is 1000 on equation (v1^2-v2^2/ 2 x 1000) and gz1/ 1000. Is it some sort of unit convertion? if yes, then in what unit?

Help me with the definition of this terms too;
- Z1
- Z2
- ΔU

Thank you!

STEP2
usiry SFEE ,
Energy In =
Energy out
P,v,++32,+Prz
(
9Z, +Q-W
Aリ=(P,-B
2X IDDD
1000
162-2702 9.81X32
DU=(600x0.37 - 100x0.62)+
2メ50D
(000
-gr 135
Du= - 20.00g K5)kg
-sign fnadicare
decremeny- Ot
A internalene9
Ang.- fnternal energy dereyeby
Option (O is correct.

STEP1
given-
work done
= 135F5
e, = 0:37 mkg V2-0.62 m)
P,こ600と Pa,
P2=100KPg
V2= 270m)s
Z,=32M,
Heat loss
inureese
To be find - check specifie internal eierTerdeereare.
eneroy
ordeerease,
and chenges of
internaleneroy A .

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