**Problem Statement** Define the function: \[ h(x) = \frac{f(x) \cdot g(x) - 10}{g(x)} \] Now suppose the following values: - \( f(2) = 7 \) - \( f'(2) = -5 \) - \( g(2) = 3 \) - \( g'(2) = -4 \) Find \( h'(2) \). **Solution Explanation** To solve for \( h'(2) \), you would typically apply the quotient rule for derivatives to the function \( h(x) \). The quotient rule states that for a function \( \frac{u(x)}{v(x)} \), the derivative is given by: \[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \] Here: - \( u(x) = f(x) \cdot g(x) - 10 \) - \( v(x) = g(x) \) You will need to find \( u'(x) \) and \( v'(x) \), and then substitute the given values to find \( h'(2) \).

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement**

Define the function:

\[ h(x) = \frac{f(x) \cdot g(x) - 10}{g(x)} \]

Now suppose the following values:

- \( f(2) = 7 \)
- \( f'(2) = -5 \)
- \( g(2) = 3 \)
- \( g'(2) = -4 \)

Find \( h'(2) \).

**Solution Explanation**

To solve for \( h'(2) \), you would typically apply the quotient rule for derivatives to the function \( h(x) \). The quotient rule states that for a function \( \frac{u(x)}{v(x)} \), the derivative is given by:

\[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \]

Here:
- \( u(x) = f(x) \cdot g(x) - 10 \)
- \( v(x) = g(x) \)

You will need to find \( u'(x) \) and \( v'(x) \), and then substitute the given values to find \( h'(2) \).
Transcribed Image Text:**Problem Statement** Define the function: \[ h(x) = \frac{f(x) \cdot g(x) - 10}{g(x)} \] Now suppose the following values: - \( f(2) = 7 \) - \( f'(2) = -5 \) - \( g(2) = 3 \) - \( g'(2) = -4 \) Find \( h'(2) \). **Solution Explanation** To solve for \( h'(2) \), you would typically apply the quotient rule for derivatives to the function \( h(x) \). The quotient rule states that for a function \( \frac{u(x)}{v(x)} \), the derivative is given by: \[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \] Here: - \( u(x) = f(x) \cdot g(x) - 10 \) - \( v(x) = g(x) \) You will need to find \( u'(x) \) and \( v'(x) \), and then substitute the given values to find \( h'(2) \).
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