Calculations:Moles KHPFlask 2: 0.7136g. Imal = 0.0034941molFlask 10.1051g204.239Imal0.00345248mol204.233Flask 3: 0.7069. Imal = 0.003461294 mol204.23Volume:Flask 1; 16.50mL.14 30.0165L1000MLFlask 2: 16.50ML. ILFlask 3; 15.80m². 12.1000mL= 0.0168 L= 0.01584Luckae1000 mlShow Transcribed Texthelp find the standard deviation andmean for this!

Given that, Flask number Number of moles (mol) Volume (L) Flask 1 0.0034741 0.0165 Flask 2…

Calculations: Moles KHP Flask 2: 0.71363. Imal = 0.0034941mol Flask 10.1051g 204.239 Imal 204.23 0.00345248mol Flask 3: 0.7069. Imal = 0.003464 294 mol 204.23 Volume: Flask 1; 16.50mL. 14 30.0165L TOOOM L Flask 2: 16.50mL. 10m² = 0.01682 1000mL Flask 3; 15.80mL. 12 Luckar 1000m² = 0.01582 ml Show Transcribed Text help find the standard deviation and mean for this!

Calculations: Moles KHP Flask 2: 0.71363. Imal = 0.0034941mol Flask 10.1051g 204.239 Imal 204.23 0.00345248mol Flask 3: 0.7069. Imal = 0.003464 294 mol 204.23 Volume: Flask 1; 16.50mL. 14 30.0165L TOOOM L Flask 2: 16.50mL. 10m² = 0.01682 1000mL Flask 3; 15.80mL. 12 Luckar 1000m² = 0.01582 ml Show Transcribed Text help find the standard deviation and mean for this!

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Use the References to access important values if needed for this question. What is the concentration of argon (in units of grams per liter) dissolved in water at 25° C, when the Ar gas over the solution has a partial pressure of 249 mm Hg? k for Ar at 25° C is 1.40x10- mol/L-atm. g/L Submit Answer Retry Entire Group 8 more group attempts remaining
4
In determining the normality of an acid, the equivalent number depends on Select one: O The number of H' ions that an acid donates or that a base accepts O The number of moles of the acid The number of electrons released by the reducing agent or accepted by the oxidizing agent The charge of the cation or anion participating in the reaction
8. For each compound, pick the better solvent for dissolving it, water or hexane (C6H14). a. I2 b. NaBr c. Ethanol, CH:CH2OH d. benzene, C6H6
Reagent nitric acid is 67.74% HNO3 by mass and its molarity is 14.33 M. Calculate the mole fraction of nitric acid in the solution. Express final answer with two decimal places.
A stock solution of 1.50 M NaCl is available. How many milliliters are needed to make 3.25 L of 0.550 M NaCl solution?
How many grams of Mg3(PO4)2 are needed to make 3.000 L of a 2.500 M solution ? The GFW for magnesium phosphate is 262.87 g. _____________ mol ( _____________ L)(–––––––––––––––––––––––) = ________________ mol _____________ L ________________ g ________________ mol (–––––––––––––––––––––––) = _____________ g _________________ mol
Please don't provide handwritten solution
Question. Determination of percent water (%H₂O) in hydrated FeSO4nH₂O is demonstrated in General Chemistry Laboratory (I), Chem. 105. The following table contains the results collected from the students groups. 1 2 3 4 نا دیا 5 6 3.38 3.47 3.35 3.40 3.44 3.41 1.4 1.35 1.35 1.44 1.49 1.39 n= Moles H₂O Mole FeSO Average n % water in hydrated salt (wt/wt) Q1) Assume MM of FeSO4 is 152 g/mol. What is the average number of water molecules in the samples? a.11.94 b.12.01 c. 12.00 d.12.09 e.11.99 Q2) What is the average % water (wt/wt) for all samples? a.59.71 b.56.68 c.58.58 d. 58.82 e.59.23 Q3) What is the average number of moles of water for all samples? a.0.11 b.0.12 c.0.13 d.0.10
What molarity of 12 mL of sulfuric acid would be present if it is diluted to 0.0875 M solution in 690 mL? 5.03 M 1.74 M 6.37 M 2.50 M 3.95 M
How would you prepare 2.50×1022.50×102 mLmL of 0.084 MM solution of MgCl2MgCl2 from a 2.00 MM stock solution?
An aqueous potassium iodate (KIO,) solution is made by dissolving 525 grams of KIO, in sufficient water so that the final 3. volume of the solution is 3.60 L. Calculate the molarity of the KIO, solution. [KIO,]= terms of use help, about us careers