Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
How many grams of C₆H₁₂O₆ is needed to make 150 mL of 0.250 M solution?
**Explanation:**
To find out how many grams of C₆H₁₂O₆ (glucose) are needed:
1. Calculate the number of moles required using the formula for molarity:
\[
\text{Moles} = \text{Molarity} \times \text{Volume (in liters)}
\]
Molarity (M) = 0.250 M, Volume = 150 mL = 0.150 L
2. Multiply the moles by the molar mass of glucose (C₆H₁₂O₆ = 180.18 g/mol) to find the mass in grams.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F69d3c8b6-4012-43b0-80a6-d85ebf5fdc33%2Fcd5c794c-d307-4c51-9b83-555c20fca1b0%2Flhdbmj4_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
How many grams of C₆H₁₂O₆ is needed to make 150 mL of 0.250 M solution?
**Explanation:**
To find out how many grams of C₆H₁₂O₆ (glucose) are needed:
1. Calculate the number of moles required using the formula for molarity:
\[
\text{Moles} = \text{Molarity} \times \text{Volume (in liters)}
\]
Molarity (M) = 0.250 M, Volume = 150 mL = 0.150 L
2. Multiply the moles by the molar mass of glucose (C₆H₁₂O₆ = 180.18 g/mol) to find the mass in grams.
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