Calculating Heat Transfer through ConductionA polystyrene foam icebox has a total area of 0.950 m2 and walls with an average thickness of 2.50 cm. The box contains ice, water, and canned beverages at 0 °C. The inside of the box is kept cold by melting ice. Howmuch ice melts in one day if the icebox is kept in the trunk of a car at 35.0 ºC ?StrategyThis question involves both heat for a phase change (melting of ice) and the transfer of heat by conduction. To find the amount of ice melted, we must find the net heat transferred. This value can be obtained by calculating the rate of heat transfer by conduction and multiplying by time.
Calculating Heat Transfer through ConductionA polystyrene foam icebox has a total area of 0.950 m2 and walls with an average thickness of 2.50 cm. The box contains ice, water, and canned beverages at 0 °C. The inside of the box is kept cold by melting ice. Howmuch ice melts in one day if the icebox is kept in the trunk of a car at 35.0 ºC ?StrategyThis question involves both heat for a phase change (melting of ice) and the transfer of heat by conduction. To find the amount of ice melted, we must find the net heat transferred. This value can be obtained by calculating the rate of heat transfer by conduction and multiplying by time.
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Calculating Heat Transfer through Conduction
A polystyrene foam icebox has a total area of 0.950 m2 and walls with an average thickness of 2.50 cm. The box contains ice, water, and canned beverages at 0 °C. The inside of the box is kept cold by melting ice. How
much ice melts in one day if the icebox is kept in the trunk of a car at 35.0 ºC ?
Strategy
This question involves both heat for a phase change (melting of ice) and the transfer of heat by conduction. To find the amount of ice melted, we must find the net heat transferred. This value can be obtained by calculating the rate of heat transfer by conduction and multiplying by time.
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