a) A house walls that are 16 cm thick and have an average thermal conductivity three times that of cork. Assume there are no windows or doors. The walls' surface area is 1450000 cm² and their inside surface is at 18 °C, while their outside surface is at 4°C. (Thermal conductivity of cork is 0.042 W/m°C) (1) Calculate the rate of heat conduction through house walls? (i) How many 200W room heaters would be needed to balance the heat transfer due to conduction? (approximate number)

a) A house walls that are 16 cm thick and have an average thermal conductivity three times that of cork. Assume there are no windows or doors. The walls' surface area is 1450000 cm² and their inside surface is at 18 °C, while their outside surface is at 4°C. (Thermal conductivity of cork is 0.042 W/m°C) (1) Calculate the rate of heat conduction through house walls? (i) How many 200W room heaters would be needed to balance the heat transfer due to conduction? (approximate number)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

a) A house walls that are 16 cm thick and have an average thermal conductivity three times that of cork.
Assume there are no windows or doors. The walls' surface area is 1450000 cm² and their inside surface is at 18
°C, while their outside surface is at 4°C. (Thermal conductivity of cork is 0.042 W/m°C)
(1) Calculate the rate of heat conduction through house walls?
(i) How many 200W room heaters would be needed to balance the heat transfer due to conduction?
(approximate number)
b) A spherical infrared heater of radius 6.2 cm has an emissivity of 0.71. What temperature must it run at if the
required power is 0.5 kW? Neglect the temperature of the environment. (Stefan's constant = 5.67*10-8 Wm-
2K-4)
The temperature of the heater in Celsius =

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