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Calculate vapor pressure of benzene at 26°C using Clausius-Clapeyron Equation. The normal boiling point of benzene is 80.1°C, and its molar heat of vaporization is 30.8kJ/mol. Instruction: Please enter your answer (in units of atm) with 3 decimal places, such as 0.234

Calculate vapor pressure of benzene at 26°C using Clausius-Clapeyron Equation. The normal boiling point of benzene is 80.1°C, and its molar heat of vaporization is 30.8kJ/mol. Instruction: Please enter your answer (in units of atm) with 3 decimal places, such as 0.234

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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QUESTION 4 Calculate vapor pressure of benzene at 26°C using Clausius-Clapeyron Equation. The normal boiling point of benzene is 80.1°C, and its molar heat of vaporization is 30.8kJ/mol. Instruction: Please enter your answer (in units of atm) with 3 decimal places, such as 0.234
Transcribed Image Text:QUESTION 4 Calculate vapor pressure of benzene at 26°C using Clausius-Clapeyron Equation. The normal boiling point of benzene is 80.1°C, and its molar heat of vaporization is 30.8kJ/mol. Instruction: Please enter your answer (in units of atm) with 3 decimal places, such as 0.234
Expert Solution
Step 1

Given that-

Temperature of benzene, T1=260C= 299 K

Normal boiling point of benzene, Ta=80.10C= 353.1 K

Pressure at boiling point, Pa=1 atm

Molar heat of vapourization, ∆HVap=30.8 kJ/mol=30800 J/mol

The Clausius-Clapeyron equation is-

lnPaP1=∆HvapR1T1-1Ta 

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