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C. Standardization Weight of vial and KHPH 59.09 Weight after Ist transfer 59.2 Weight after 2nd transfer 56-5 Weight after 3rd transfer S5.6 Weight of KHPh in flask I (show calculations) 0-29 So 9- S62 Weight of KHPh in flask II (show calculations) 1-79 Sa a- 56.5 Weight of KHPH in flask III (show calculations) 0.99 56.5-55-6 II III Initial volume reading of NaOH O-00 ml 27.00 S1-00 Final volume reading of NaOH as.0oml SI-00 80-00 Volume of NAOH used 25-00 ml 24.00 ml 29.00ml Molarity of NAOH Show calculations for all Trials Below:

C. Standardization Weight of vial and KHPH 59.09 Weight after Ist transfer 59.2 Weight after 2nd transfer 56-5 Weight after 3rd transfer S5.6 Weight of KHPh in flask I (show calculations) 0-29 So 9- S62 Weight of KHPh in flask II (show calculations) 1-79 Sa a- 56.5 Weight of KHPH in flask III (show calculations) 0.99 56.5-55-6 II III Initial volume reading of NaOH O-00 ml 27.00 S1-00 Final volume reading of NaOH as.0oml SI-00 80-00 Volume of NAOH used 25-00 ml 24.00 ml 29.00ml Molarity of NAOH Show calculations for all Trials Below:

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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I need help with molarity of NaOH
volume of the added sodium hydroxide is noted, and the concentration of the NaOH is calculated. SAMPLE OF CALCULATIONS 50 ml of NaOH solution is used to titrate 1.0 g of KHph to the end point. Calculate the molarity of NaOH solution? KHPh used = 1.00 g Volume of NaOH used = 0.0500 L 1 mole 1 mole NaOH Moles of NaOH = 1.00g KHPH x = 4.90x 10¯ 3 204 g 4.90x 103 moles 1 mole KHPh MolarityNaOH -= 0.0980M 5.00x 10²1
Transcribed Image Text:volume of the added sodium hydroxide is noted, and the concentration of the NaOH is calculated. SAMPLE OF CALCULATIONS 50 ml of NaOH solution is used to titrate 1.0 g of KHph to the end point. Calculate the molarity of NaOH solution? KHPh used = 1.00 g Volume of NaOH used = 0.0500 L 1 mole 1 mole NaOH Moles of NaOH = 1.00g KHPH x = 4.90x 10¯ 3 204 g 4.90x 103 moles 1 mole KHPh MolarityNaOH -= 0.0980M 5.00x 10²1
1:48 1 YouTube C. Standardization Weight of vial and KHPH 59-09 Weight after 1st transfer 59-a Weight after 2nd transfer 56-5 Weight after 3rd transfer 55.6 Weight of KHPH in flask I (show calculations) 50-9- 562 Weight of KHPh in flask II (show calculations) 1-79 Sa a-56.5 Weight of KHPh in flask III (show calculations) 0-99 56.5-55-6 I II III Initial volume reading of NaOH O-00 ml 27. 00 S1-00 Final volume reading of NaOH as-0oml SI-00 80-00 Volume of NaOH used a5-00 ml 24.00 ml 29:00ml Molarity of NaOH Show calculations for all Trials Below:
Transcribed Image Text:1:48 1 YouTube C. Standardization Weight of vial and KHPH 59-09 Weight after 1st transfer 59-a Weight after 2nd transfer 56-5 Weight after 3rd transfer 55.6 Weight of KHPH in flask I (show calculations) 50-9- 562 Weight of KHPh in flask II (show calculations) 1-79 Sa a-56.5 Weight of KHPh in flask III (show calculations) 0-99 56.5-55-6 I II III Initial volume reading of NaOH O-00 ml 27. 00 S1-00 Final volume reading of NaOH as-0oml SI-00 80-00 Volume of NaOH used a5-00 ml 24.00 ml 29:00ml Molarity of NaOH Show calculations for all Trials Below:
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It is a Titration Method to Standardise NaOH Solution by Using KHP 

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