College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![**Calculate the work (in joules) done if 840 watts are used for 5 seconds.**
**Your Answer:**
---
To calculate the work done, use the formula:
\[ \text{Work (in joules)} = \text{Power (in watts)} \times \text{Time (in seconds)} \]
Given:
- Power = 840 watts
- Time = 5 seconds
Substitute these values into the formula:
\[ \text{Work} = 840 \, \text{watts} \times 5 \, \text{seconds} = 4200 \, \text{joules} \]
Therefore, the work done is 4200 joules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd37b8355-3342-4bc2-a734-288bda306920%2Fb53af7fb-9f50-4aeb-bf4c-74a5c4ac1f73%2Fwryckz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Calculate the work (in joules) done if 840 watts are used for 5 seconds.**
**Your Answer:**
---
To calculate the work done, use the formula:
\[ \text{Work (in joules)} = \text{Power (in watts)} \times \text{Time (in seconds)} \]
Given:
- Power = 840 watts
- Time = 5 seconds
Substitute these values into the formula:
\[ \text{Work} = 840 \, \text{watts} \times 5 \, \text{seconds} = 4200 \, \text{joules} \]
Therefore, the work done is 4200 joules.
![**Question:**
Calculate the gravitational potential energy of a 27 kg mass located 5 meters above the surface of the earth?
**Your Answer:**
*Explanation:*
Gravitational potential energy (GPE) can be calculated using the formula:
\[ \text{GPE} = m \cdot g \cdot h \]
Where:
- \( m \) is the mass in kilograms (kg)
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \) on Earth)
- \( h \) is the height in meters (m) above the ground
In this problem:
- \( m = 27 \, \text{kg} \)
- \( h = 5 \, \text{m} \)
Plugging these values into the formula gives:
\[ \text{GPE} = 27 \cdot 9.81 \cdot 5 \]
Carry out the multiplication to find the gravitational potential energy.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd37b8355-3342-4bc2-a734-288bda306920%2Fb53af7fb-9f50-4aeb-bf4c-74a5c4ac1f73%2F7k3ru7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
Calculate the gravitational potential energy of a 27 kg mass located 5 meters above the surface of the earth?
**Your Answer:**
*Explanation:*
Gravitational potential energy (GPE) can be calculated using the formula:
\[ \text{GPE} = m \cdot g \cdot h \]
Where:
- \( m \) is the mass in kilograms (kg)
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \) on Earth)
- \( h \) is the height in meters (m) above the ground
In this problem:
- \( m = 27 \, \text{kg} \)
- \( h = 5 \, \text{m} \)
Plugging these values into the formula gives:
\[ \text{GPE} = 27 \cdot 9.81 \cdot 5 \]
Carry out the multiplication to find the gravitational potential energy.
Expert Solution

Step 1
Given:-
The power P = 840 Watt
The time t = 5 sec
Find:-
a) The work done
b) if the mass of the object is m = 27 kg and the height of the mass is h = 5 m then gravitational potential energy?
Step by step
Solved in 4 steps
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