Calculate the weight % of each component in an unknown sample of volatiles using Area Normalization. Given the following information use ethanol as the internal standard. Standard Unknown sample Component Weight used (mg) Raw Peak Area Component Raw Peak Area Ethanol 498.3 5104 Ethanol 3495 Hexane 756.4 9285 Hexane 3267 Benzene 412.7 4374 Benzene 2894 Ethyl acetate 628.9 7239 Ethyl acetate 5402 Calculate the absolute error between the normalized area percentages and the calculated weight percentages of the unknown components.

Calculate the weight % of each component in an unknown sample of volatiles using Area Normalization. Given the following information use ethanol as the internal standard. Standard Unknown sample Component Weight used (mg) Raw Peak Area Component Raw Peak Area Ethanol 498.3 5104 Ethanol 3495 Hexane 756.4 9285 Hexane 3267 Benzene 412.7 4374 Benzene 2894 Ethyl acetate 628.9 7239 Ethyl acetate 5402 Calculate the absolute error between the normalized area percentages and the calculated weight percentages of the unknown components.

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter14: Chromatography

Section: Chapter Questions

Problem 9P

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Calculate the weight % of each component in an unknown sample of volatiles using Area Normalization. Given the following information use ethanol as the internal standard. Standard Unknown sample Component Weight used (mg) Raw Peak Area Component Raw Peak Area Ethanol 498.3 5104 Ethanol 3495 Hexane 756.4 9285 Hexane 3267 Benzene 412.7 4374 Benzene 2894 Ethyl acetate 628.9 7239 Ethyl acetate 5402 Calculate the absolute error between the normalized area percentages and the calculated weight percentages of the unknown components.
Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72
how can i plot this data with a regression line and including r^2 term?
Please help to.identify all peaks
Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
When two predictors are highly correlated, which of the following statements is true? -Ridge regression will usually have non-zero coefficients for both predictors. -Ridge Regression will drive coefficients to zero for both features. -Lasso regression will usually have non-zero coefficients for both predictors. -Elastic net will usually have non-zero coefficients for both predictors select the correct option
Study the tabulated data during an gravimetric analysis of BaSO4 experiment Trial T1 T2 T3 Mass of sample (g) 1.0040 1.0100 1.0050 Constant weight of empty crucible (g) 10.2453 10.2454 10.2454 Constant weight after ignition (g) 10.3253 10.3252 10.3253 1. Calculate the mean mass of precipitate as BaSO4 a. 0.0799 g b. 0.0800 c. 0.08 g 2. Calculate the mean weight of sulphate (MM BaSO4 = 233.39 g/mol, So42- = 176 g/mol)? a. 0.0603 g b. 0.06 g c. 0.06025 g 3. Calculate the mean % SO42- in the sample a. 6.00% b. 5.991% c. 5.9908%
Find the molar mass given all this data
1. Use the following Absorbance Data to generate a Bradford Assay Standard Curve. Protein Concentration Absorbance at 595nm (mg/mL) 0.05 Chart Title 0.0092 0.1 0.02 0.2 0.04 0.3 0.112 0.4 0.167 0.5 0.1980 0.6 0.2436 Absorbance at 595nm 0.3 4y = 0.4499x - 0.0254 R? = 0.9824 0.25 0.2 0.15 0.1 0.05 0.1 0.2 0,3 0.4 0,5 0.6 0.7
(81310 - 76200) ÷ 0.00216 With Sig Figs
Value Number of sig figs 301.50 0.0500 2650 7.560 x 1023
Paraxylene, styrene, toluene, and benzene are to be separated with the array of distillation columns shown in the following figure. Calculate the molar flow rates of D1, D2, B1, and B2. 6% Xylane 5% Styrene 51% Toluene 38% Benzene 19% Xylene 21% Styrene 36% Tolvene 24% Berazene 22% Xylene B, 20% Styrene 46% Tohvene 12% Benzene D, 18% Xylene 9% Styrene 42% Tohene 31% Benzene F= 70 kg-molimin B 28% Xylene 63% Styrene 8% Tohuene 1% Benzene a- Using the polymath software. b- Using the Excel solver. c- Using Gauss Elimination method. d- Find the inverse by Gauss Jordan then find the solution of the system. e- Using LU factorization.

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Standard	Unknown sample
Component	Weight used (mg)	Raw Peak Area	Component	Raw Peak Area
Ethanol	498.3	5104	Ethanol	3495
Hexane	756.4	9285	Hexane	3267
Benzene	412.7	4374	Benzene	2894
Ethyl acetate	628.9	7239	Ethyl acetate	5402