Calculate the volume (in mL) of 0.100 M Na2Co3 needed to produce 1.00 g of CaCo3 (s). There is an excess of CaCl2. Molar Mass of calcium carbonate = 100.09 g/mol
Calculate the volume (in mL) of 0.100 M Na2Co3 needed to produce 1.00 g of CaCo3 (s). There is an excess of CaCl2. Molar Mass of calcium carbonate = 100.09 g/mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2) Calculate the volume (in mL) of 0.100 M Na2Co3 needed to produce 1.00 g of CaCo3 (s). There is an excess of CaCl2.
Molar Mass of calcium carbonate = 100.09 g/mol

Transcribed Image Text:Compare moles of calcium carbonate to moles of sodium carbonate based on balanced equation to calculate moles of sodium carbonate required
Step 3
Compute the volume of sodium carbonate solution required
Step 4
Convert the volume of sodium carbonate solution required from liters to milliliters
2) Na, CO3(ag) + CaCl2 (aq)
→ 2 NaCl(aq) + CaCO3(s)
Calculate the volume (in mL) of 0.100 M NagCO3 needed to produce 1.00 g of CaCO3 (s). There is an excess of CaCl,.
Molar mass of calcium carbonate = 100.09 g/mol
Volume of sodium carbonate D
mL
METHODS
) RESET
MY NOTES A LAB DATA
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Expert Solution

Step 1
Given reaction:
Na2CO3 + CaCl2 ------> CaCO3 + 2NaCl
Molar mass of CaCO3 = 100.09 g/mole
Molarity of Na2CO3 solution, M= 0.100 M
To be calculated:
Volume of solution in ml
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