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Calculate the value of ∆H°rxn for the reaction: N2H4(l) + O2(g) → N2(g) + 2 H2O (l) Using the following thermochemical reactions ∆H°rxn = N2O (g) + 3 H2 (g) → N2H4(l) + H2O (l) ∆H°rxn = -317.0 kJ 2 NH3(g) + 3 N2O (g) → 4 N2(g) + 3 H2O(l) ∆H°rxn = -1010.0 kJ 2 NH3(g) + ½ O2 (g) → N2H4(l) + H2O(l) ∆H°rxn = -143.0 kJ H2(g) + ½ O2(g) → H2O (l) ∆H°rxn = -286.0 kJ

Calculate the value of ∆H°rxn for the reaction: N2H4(l) + O2(g) → N2(g) + 2 H2O (l) Using the following thermochemical reactions ∆H°rxn = N2O (g) + 3 H2 (g) → N2H4(l) + H2O (l) ∆H°rxn = -317.0 kJ 2 NH3(g) + 3 N2O (g) → 4 N2(g) + 3 H2O(l) ∆H°rxn = -1010.0 kJ 2 NH3(g) + ½ O2 (g) → N2H4(l) + H2O(l) ∆H°rxn = -143.0 kJ H2(g) + ½ O2(g) → H2O (l) ∆H°rxn = -286.0 kJ

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Calculate the value of ∆H°rxn for the reaction: N2H4(l) + O2(g) → N2(g) + 2 H2O (l)

Using the following thermochemical reactions ∆H°rxn =
N2O (g) + 3 H2 (g) → N2H4(l) + H2O (l) ∆H°rxn = -317.0 kJ
2 NH3(g) + 3 N2O (g) → 4 N2(g) + 3 H2O(l) ∆H°rxn = -1010.0 kJ
2 NH3(g) + ½ O2 (g) → N2H4(l) + H2O(l) ∆H°rxn = -143.0 kJ
H2(g) + ½ O2(g) → H2O (l) ∆H°rxn = -286.0 kJ
 

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