Calculate the value for the change in magnetic field inside the solenoid, the changing flux in the solenoid and the Induced EMF which results

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A solenoid with 1000 turns of insulated wire in a length of 40 cm has a diameter of 20 cm.  An alternating current through the coils has a value of 120 Amps/sec.  Calculate the value for the change in magnetic field inside the solenoid, the changing flux in the solenoid and the Induced EMF which results. 

a) Calculate the time rate of change of magnetic field in the solenoid for the given values above. 

b)Considering the Area and total number of coils in the solenoid, find the EMF generated while the magnetic field is changing.  

 
Expert Solution
Change in magnetic field inside the solenoid:

Given , N=1000

           Length=l=40cm=0.4m

            radius=r=diameter/2=20/2=10cm=0.10m

           dI/dt=120A/sec

Change in magnetic field=B=μ0NIl=4π×10-7×1000×1200.4=0.37 Wb=377 mWb

Change in magnetic flux=φ=BA=Bπr2=0.37×π×0.1×0.1=12mWbm2

   

 

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