Calculate the terminal voltage for a battery with an internal resistance of 0.835 N and an emf of 4.90 V when the battery is connected in series with an 70.6 N resistor.

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Chapter1: Units, Trigonometry. And Vectors
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Please help me with both parts of this problem, and double check your answers, i have had many issues with tutors in the past giving incorrect answers, and thats of no use to me then

**Problem 26.1**

### Part A
Calculate the terminal voltage for a battery with an internal resistance of 0.835 Ω and an emf of 4.90 V when the battery is connected in series with an 70.6 Ω resistor.

\[ V_{ab} = \]

**Submit** `[Submit Button]` `[Request Answer]`

### Part B
Calculate the terminal voltage for a battery with an internal resistance of 0.835 Ω and an emf of 4.90 V when the battery is connected in series with an 706 Ω resistor.

\[ V_{ab} = \]

**Submit** `[Submit Button]` `[Request Answer]`

**Explanation:**
- **Part A and Part B** ask for the terminal voltage calculation for a battery under different load conditions.
- **Terminal Voltage (V_ab)** of a battery can be calculated using the formula:
  \[ V_{ab} = E - I \cdot r \]
  where:
  - \( E \) is the electromotive force (emf) of the battery.
  - \( I \) is the current flowing through the circuit.
  - \( r \) is the internal resistance of the battery.

- The current \( I \) in the series circuit can be computed using Ohm's Law:
  \[ I = \frac{E}{R + r} \]
  where:
  - \( R \) is the resistance of the external resistor connected in series with the battery.

- Substituting this current back into the terminal voltage formula provides the terminal voltage for each part.

**Usage on Educational Websites:**
- This problem set demonstrates the concepts of internal resistance and terminal voltage in electrical circuits.
- Students can use the provided information and formulas to calculate required values and understand the impact of different resistances on the terminal voltage of a battery.
Transcribed Image Text:**Problem 26.1** ### Part A Calculate the terminal voltage for a battery with an internal resistance of 0.835 Ω and an emf of 4.90 V when the battery is connected in series with an 70.6 Ω resistor. \[ V_{ab} = \] **Submit** `[Submit Button]` `[Request Answer]` ### Part B Calculate the terminal voltage for a battery with an internal resistance of 0.835 Ω and an emf of 4.90 V when the battery is connected in series with an 706 Ω resistor. \[ V_{ab} = \] **Submit** `[Submit Button]` `[Request Answer]` **Explanation:** - **Part A and Part B** ask for the terminal voltage calculation for a battery under different load conditions. - **Terminal Voltage (V_ab)** of a battery can be calculated using the formula: \[ V_{ab} = E - I \cdot r \] where: - \( E \) is the electromotive force (emf) of the battery. - \( I \) is the current flowing through the circuit. - \( r \) is the internal resistance of the battery. - The current \( I \) in the series circuit can be computed using Ohm's Law: \[ I = \frac{E}{R + r} \] where: - \( R \) is the resistance of the external resistor connected in series with the battery. - Substituting this current back into the terminal voltage formula provides the terminal voltage for each part. **Usage on Educational Websites:** - This problem set demonstrates the concepts of internal resistance and terminal voltage in electrical circuits. - Students can use the provided information and formulas to calculate required values and understand the impact of different resistances on the terminal voltage of a battery.
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