Calculate the temporary and permanent hardness of water sample containing Mg(HCO3)2= 7.3mg/L, Ca(HCO3)2= 16.2mg/L, MgC12= 9.5mg/L, CaSO4=13.6mg/L)
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- Analysis of a given water sample gave the following results: Ca(HCO3)2 = 40.5 ppm, Mg(HCO3)2 = 36.5 ppm, MgSO4= 30 ppm, CaSO4 = 34 ppm, CaCl₂ = 27.75 ppm and NaCl = 10 ppm. a) Give values of temporary and permanent hardness in ppm CaCO3 equivalent and ° Clark. b) Calculate the amount of lime and soda used for softening 20,000 L of water. Given purity of lime is 84% and purity of soda is 92%. c) Calculate the volume of 0.01 (M) EDTA required to titrate 10 mL of same water sample using EBT as indicator. d) The hardness of 15,000 L of above water sample was completely removed by passing it through a zeolite softener. The zeolite softener required 100 L of NaCl solution for regeneration. Calculate the concentration of the NaCl solution.d. 1.10 g of K3PO4 in 430.0 mL of solution Mx+ =| M %3D Mpo, MC. Electrolytes in Body Fluids 1. Type of IV Solution 5% Isolute P (mEa/L) Plasnalyte (mEg/L) Lactated Ringer's (mEg/L) Nal+ = 130 Klt = 4 Ca2+ = 3 Nal+ = 25 K+ = 20 Nal+ = 140 Kl+ = 5 2. Cations %3D %3D Mg+ = 3 Mg2+ = 3 CI- = 22 HPO- =3 Acl- = 23 CI- = 98 Glu'-= 23 Acl- = 27 3. Anions CI'- = 109 %3D HPO = 28 %3D %3D 4. Total Charge of Cations (+) 137 137 5. Total Charge of Anions (-) 6. Sum of the Charges Copyright 2014 Pearson Education, Inc.
- 3. The following mineral analysis was reported for a water sample taken from a local NJ well. Determine the total, carbonate and non-carbonate hardness in mg/L as CaCO3. Well No. 1, Lab No. 02694, November 9, 1971 Iron 0.2 Silica (SiO2) 20.0 Manganese 0.0 Fluoride 0.35 Ammonium 0.5 Boron 0.1 Sodium 4.7 Nitrate 0.0 Potassium 0.9 Chloride 4.5 Calcium 67.2 Sulfate 29.0 Magnesium 40.0 Alkalinity 284.0 as CACO3 Barium 0.5 pH 7.6 units Note: All reported as "mg/L as the ion" unless stated otherwise. Ca2 Alk NonPrepare the following solutions: 100.0 mL 0.0500 M stock Ca2+ solution 50.0 mL 0.0050 M working standard Ca2+ solution from 0.0500 M Ca2+Calculate the solubility of CuCO3 in water at 25C. Ksp = 3.00x10-12. Round the answer to two significant figures.
- Hydroxyapatite, Ca₁0 (PO4) 6 (OH)2, has a solubility constant of Ksp = 2.34 x 10-59, and dissociates according to Ca10 (PO4)(OH)2(s) = 10 Ca²+(aq) + 6 PO¾-¯(aq) + 2 OH(aq) Solid hydroxyapatite is dissolved in water to form a saturated solution. What is the concentration of Ca²+ in this solution if [OH] is fixed at 3.60 × 10-4 M? [Ca2+] = MWhat volume (whole number mL) of glycerol (SCE = 0.35, density = 1.25 g cm-3) are required to prepare 75 mL of a concentrated solution, which on dilution to 1.21 litres with water gives an isotonic lotion containing 0.26% w/v neomycin sulphate (SCE = 0.11)?Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?
- You are required to prepare 5 L of a solution containing 1.000 x 103 mol/L of Cu2"(aq). Which of the following procedures would produce an appropriate solution? O Dissolve 0.0636 g of copper metal in nitric acid, add to a 5.000 Lvolumetric flask, dilute to the mark with deionized water and mix well. O Dissolve 1.248 g of CuSO.5H,0(s) in deionized water, add to a 5.000 L volumetric flask, dilute to the mark with deionized water and mix well. Dissolve 0.250 g of CUSO,.5H,O(s) in deionized water, add to a 5.000 L volumetric flask, dilute to the mark with deionized water and mix well.Please don't provide handwritten solution...Preparation of 100 ml 1.0 molar (1.0M) H2SO4 solution (specific gravity, 1.8 g/ml and purity, 98%). H2SO4 molecular weight is 98 grams.