Calculate the temporary and permanent hardness of water sample containing Mg(HCO3)2= 7.3mg/L, Ca(HCO3)2= 16.2mg/L, MgC12= 9.5mg/L, CaSO4=13.6mg/L)
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- Calculate the temporary and total hardness of a water sample containing Mg(HCO3)2= 73mg/L, Ca(HCO3)2= 162mg/L, M9C12= 95mg/L, CaSO4=136mg/L.Determine the exact hardness in units of mg/L as CaCO3. Ba2+ contributes to hardness as well.The water quality from a well test is given below. If the target hardness is 95 mg/L as CACO3, determine the amount of quicklime (mg/L as CaQ) and Soda (mg/L as Na,CO3) required. Constituents- mg/L CO2 13 НСОЗ- 180 Ca+2 59 SO4-2 90 Mg+2 23 CI- 12 K+ 15 Br 4.5
- Analysis of a given water sample gave the following results: Ca(HCO3)2 = 40.5 ppm, Mg(HCO3)2 = 36.5 ppm, MgSO4= 30 ppm, CaSO4 = 34 ppm, CaCl₂ = 27.75 ppm and NaCl = 10 ppm. a) Give values of temporary and permanent hardness in ppm CaCO3 equivalent and ° Clark. b) Calculate the amount of lime and soda used for softening 20,000 L of water. Given purity of lime is 84% and purity of soda is 92%. c) Calculate the volume of 0.01 (M) EDTA required to titrate 10 mL of same water sample using EBT as indicator. d) The hardness of 15,000 L of above water sample was completely removed by passing it through a zeolite softener. The zeolite softener required 100 L of NaCl solution for regeneration. Calculate the concentration of the NaCl solution.A sample of water is found to contain Ca(HCO3)2 = 40.5, Mg(HCO3)2 =46.5, CaSO4=32.1, CaCl2=22.45, MgSO4= 27.6, SiO2=13.5, NaCl= 15.4 mg/L. Calculate Temporary, permanent and total hardness in degree French.4) Given the following analyses of groundwater (reported as mg/L): Ca²+ = 16.5; Mg2+ = 3.1; Na = 13; K+ = 2.6; (bicarbonate) HCO3 = 67; SO4² = 18; Cl = 5.9, and SiO₂ (uncharged species) = 35 a. Calculate the analytical error of this set of analyses. b. Calculate the total dissolved solids (TDS) of the solution (sum concentration as mg/L for all species)?
- C. Electrolytes in Body Fluids 1. Type of IV Solution 5% Isolute P (mEa/L) Plasnalyte (mEg/L) Lactated Ringer's (mEg/L) Nal+ = 130 Klt = 4 Ca2+ = 3 Nal+ = 25 K+ = 20 Nal+ = 140 Kl+ = 5 2. Cations %3D %3D Mg+ = 3 Mg2+ = 3 CI- = 22 HPO- =3 Acl- = 23 CI- = 98 Glu'-= 23 Acl- = 27 3. Anions CI'- = 109 %3D HPO = 28 %3D %3D 4. Total Charge of Cations (+) 137 137 5. Total Charge of Anions (-) 6. Sum of the Charges Copyright 2014 Pearson Education, Inc.3. The following mineral analysis was reported for a water sample taken from a local NJ well. Determine the total, carbonate and non-carbonate hardness in mg/L as CaCO3. Well No. 1, Lab No. 02694, November 9, 1971 Iron 0.2 Silica (SiO2) 20.0 Manganese 0.0 Fluoride 0.35 Ammonium 0.5 Boron 0.1 Sodium 4.7 Nitrate 0.0 Potassium 0.9 Chloride 4.5 Calcium 67.2 Sulfate 29.0 Magnesium 40.0 Alkalinity 284.0 as CACO3 Barium 0.5 pH 7.6 units Note: All reported as "mg/L as the ion" unless stated otherwise. Ca2 Alk NonFind the normality of 0.0294 g K2Cr2O7 (MM = 294.19) dissolved in 125 mL solution.
- Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?Use the following atomic masses (in g/mol): As = 74.92; O = 16; K = 39.1; Cr = 52; Na = 23; Cl = 35.45; Ba = 137.33; S = 32.06, What is the normality of I2 solution where 35mL of it was found to be equivalent to 175.34mg of As2O3?Q5/ Calculate the concentration of sodium ion in grams per liter after mixing 150mL of 0.200 M NaCl and 250ml of 0.250 M Na,S04. (20M) Atom weight = Na = 22.9897, Cl = 35.453, O = 16 H=1S = 32.065, Ca = 40.078 Ba = 137.327, C= 12.0107, N = 14.0067