Calculate the support reactions at A and B for the loaded beam. Assume P = 143 lb, w = 92 lb/ft, a = 3.2 ft, and b = 7.0 ft. L A _a. P b W B

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### Calculating Support Reactions for a Loaded Beam

In this example, we will calculate the support reactions at points \(A\) and \(B\) for the loaded beam.

#### Given Data:
- Force \(P = 143 \text{ lb}\)
- Distributed Load \(w = 92 \text{ lb/ft}\)
- Distance \(a = 3.2 \text{ ft}\)
- Distance \(b = 7.0 \text{ ft}\)

#### Diagram Explanation:
The diagram provided illustrates a beam supported at two points, \(A\) (fixed support) and \(B\) (roller support). The following elements are depicted:

- **Support at A:** This support can provide reactions in both the horizontal (\(A_x\)) and vertical (\(A_y\)) directions.
- **Support at B:** This is a roller support that provides a vertical reaction (\(B_y\)).
- **Point Load \(P\)** applied vertically downward at a distance \(a\) from support \(A\).
- **Distributed Load \(w\):** The load varies linearly across the span from point \(A\) to point \(B\).
- **Coordinates:** \(x\) represents the horizontal axis, while \(y\) represents the vertical axis.

#### Calculation Objective:
We need to compute the reactions at the supports \(A_x\), \(A_y\), and \(B_y\).

#### Calculation Steps:
1. **Sum of Horizontal Forces:**
   \[ \Sigma F_x = 0 \]
   \[ A_x = 0 \] 

2. **Sum of Vertical Forces:**
   \[ \Sigma F_y = 0 \]
   \[ A_y + B_y - P - w \times (a + b) = 0 \]
  
3. **Moment Around Point A:**
   \[ \Sigma M_A = 0 \]
   \[ -P \times a - \left( \frac{w \times (a + b) \times (a + b/2)}{2} \right) + B_y \times (a + b) = 0 \]

By solving these equations, the values for \(A_y\) and \(B_y\) can be determined. Insert these computed values:

#### Answers:
- \( A_x =  \)
- \( A_y =  \)
-
Transcribed Image Text:### Calculating Support Reactions for a Loaded Beam In this example, we will calculate the support reactions at points \(A\) and \(B\) for the loaded beam. #### Given Data: - Force \(P = 143 \text{ lb}\) - Distributed Load \(w = 92 \text{ lb/ft}\) - Distance \(a = 3.2 \text{ ft}\) - Distance \(b = 7.0 \text{ ft}\) #### Diagram Explanation: The diagram provided illustrates a beam supported at two points, \(A\) (fixed support) and \(B\) (roller support). The following elements are depicted: - **Support at A:** This support can provide reactions in both the horizontal (\(A_x\)) and vertical (\(A_y\)) directions. - **Support at B:** This is a roller support that provides a vertical reaction (\(B_y\)). - **Point Load \(P\)** applied vertically downward at a distance \(a\) from support \(A\). - **Distributed Load \(w\):** The load varies linearly across the span from point \(A\) to point \(B\). - **Coordinates:** \(x\) represents the horizontal axis, while \(y\) represents the vertical axis. #### Calculation Objective: We need to compute the reactions at the supports \(A_x\), \(A_y\), and \(B_y\). #### Calculation Steps: 1. **Sum of Horizontal Forces:** \[ \Sigma F_x = 0 \] \[ A_x = 0 \] 2. **Sum of Vertical Forces:** \[ \Sigma F_y = 0 \] \[ A_y + B_y - P - w \times (a + b) = 0 \] 3. **Moment Around Point A:** \[ \Sigma M_A = 0 \] \[ -P \times a - \left( \frac{w \times (a + b) \times (a + b/2)}{2} \right) + B_y \times (a + b) = 0 \] By solving these equations, the values for \(A_y\) and \(B_y\) can be determined. Insert these computed values: #### Answers: - \( A_x = \) - \( A_y = \) -
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