Calculate the standard Gibbs free energy changes at 25 °C for each of the reactions shown below using the E° values given. Select whether each of these reactions is nonspontaneous, at equilibrium, or spontaneous under standard conditions. (a) 1 Mn²+ (aq) + 1 Ca(s) = 1 Mn(s) + 1 Ca²+ (aq) E° = 1.690 V O nonspontaneous O at equilibrium O spontaneous (b) 2 Li+ (aq) + 2 F'(aq) = 2 Li(s) + 1 F₂(0) E° = -5.920 V O nonspontaneous O at equilibrium O spontaneous AGº- AG- (c) 1 Fe²+ (aq) + 1 Hg(1) = 1 Fe(s) + 1 Hg²+ (aq) E° = -1.294 V AG- O nonspontaneous O at equilibrium O spontaneous (d) 1 Cr³+ (aq) + 1 Ce³+ (aq) = 1 Cr²+ (aq) + 1 Ce++ (aq) Eº = -2.020 V AG° = O nonspontaneous O at equilibrium O spontaneous kJ/mol kJ/mol kJ/mol kJ/mol

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(a) Choose all of the statements from below which correctly describe issues pertaining to the relationship between the emf of a reaction and its Gibbs free energy change.
The Gibbs free energy change and emf values of a reaction have opposite algebraic signs (+ vs. -).
A spontaneous reaction has a negative Gibbs free energy change and a positive emf.
A spontaneous reaction has a positive Gibbs free energy change and a negative emf.
O Electron stoichiometry must be used to interconvert a Gibbs free energy change and a reaction emf.
O A Gibbs free energy change involves coulombs of substances whereas an emf involves moles of electrons.
Transcribed Image Text:(a) Choose all of the statements from below which correctly describe issues pertaining to the relationship between the emf of a reaction and its Gibbs free energy change. The Gibbs free energy change and emf values of a reaction have opposite algebraic signs (+ vs. -). A spontaneous reaction has a negative Gibbs free energy change and a positive emf. A spontaneous reaction has a positive Gibbs free energy change and a negative emf. O Electron stoichiometry must be used to interconvert a Gibbs free energy change and a reaction emf. O A Gibbs free energy change involves coulombs of substances whereas an emf involves moles of electrons.
Calculate the standard Gibbs free energy changes at 25 °C for each of the reactions shown below using the Eº values given. Select whether each of these reactions is nonspontaneous, at equilibrium, or spontaneous under standard conditions.
(a) 1 Mn²+ (aq) + 1 Ca(s) = 1 Mn(s) + 1 Ca²+ (aq) E° = 1.690 V
O nonspontaneous
O at equilibrium
O spontaneous
AG° =
(b) 2 Li+ (aq) + 2 F (aq) = 2 Li(s) + 1 F₂(g) E° = -5.920 V AG° =
O nonspontaneous
O at equilibrium
O spontaneous
(c) 1 Fe²+ (aq) + 1 Hg(1) ⇒ 1 Fe(s) + 1 Hg²+ (aq) E° = -1.294 V AG° =
O nonspontaneous
O at equilibrium
O spontaneous
(d) 1 Cr³+ (aq) + 1 Ce³+ (aq) = 1 Cr²+ (aq) + 1 Ce4+ (aq)
O nonspontaneous
O at equilibrium
O spontaneous
E° -2.020 V AG⁰ =
kJ/mol
kJ/mol
kJ/mol
kJ/mol
Transcribed Image Text:Calculate the standard Gibbs free energy changes at 25 °C for each of the reactions shown below using the Eº values given. Select whether each of these reactions is nonspontaneous, at equilibrium, or spontaneous under standard conditions. (a) 1 Mn²+ (aq) + 1 Ca(s) = 1 Mn(s) + 1 Ca²+ (aq) E° = 1.690 V O nonspontaneous O at equilibrium O spontaneous AG° = (b) 2 Li+ (aq) + 2 F (aq) = 2 Li(s) + 1 F₂(g) E° = -5.920 V AG° = O nonspontaneous O at equilibrium O spontaneous (c) 1 Fe²+ (aq) + 1 Hg(1) ⇒ 1 Fe(s) + 1 Hg²+ (aq) E° = -1.294 V AG° = O nonspontaneous O at equilibrium O spontaneous (d) 1 Cr³+ (aq) + 1 Ce³+ (aq) = 1 Cr²+ (aq) + 1 Ce4+ (aq) O nonspontaneous O at equilibrium O spontaneous E° -2.020 V AG⁰ = kJ/mol kJ/mol kJ/mol kJ/mol
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