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Calculate the standard free energy change (kJ/mol) for the reaction shown at a temperature of 298.15 K using the information provided.   Reaction ΔHrxn (kJ/mol) ΔSrxn (J/mol-K) 2 N2(g) + 3 O2(g) → 2 N2O3(g) 167.4 -374.5

Calculate the standard free energy change (kJ/mol) for the reaction shown at a temperature of 298.15 K using the information provided.   Reaction ΔHrxn (kJ/mol) ΔSrxn (J/mol-K) 2 N2(g) + 3 O2(g) → 2 N2O3(g) 167.4 -374.5

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Calculate the standard free energy change (kJ/mol) for the reaction shown at a temperature of 298.15 K using the information provided.  

Reaction ΔHrxn (kJ/mol) ΔSrxn (J/mol-K)
2 N2(g) + 3 O2(g) → 2 N2O3(g) 167.4 -374.5
Expert Solution
Step 1

According to the question we have a reaction between the nitrogen gas and oxygen gas which is as follows,

                                   2 N2(g) + 3O2(g) → 2N2O3(g)

The temperature of the reaction is given by = T= 298.15 K

The change in the enthalpy for the reaction is given by = ∆H = 167.4 KJ/mole

The change in the entropy for the reaction is given by = ∆S = -374.5 J/mole K

In this reaction, we have to find the standard free energy change = ∆G 

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