Calculate the speed of a proton in (m/s) that is accelerated from rest through an electric potential difference of 178 V. m.-=9.11 x 10-31kg = 1.66 x 10-27kg me+ de+ =9e-=1.6× 10-1ºC Note: Answer will be in two decimal places
Calculate the speed of a proton in (m/s) that is accelerated from rest through an electric potential difference of 178 V. m.-=9.11 x 10-31kg = 1.66 x 10-27kg me+ de+ =9e-=1.6× 10-1ºC Note: Answer will be in two decimal places
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 3P: Calculate the speed of a proton that is accelerated from rest through an electric potential...
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![Calculate the speed of a proton in (m/s) that is accelerated from rest
through an electric potential difference of 178 V.
m.-= 9.11 x 10-31kg
me+=1.66 x 10-27kg
de+ =9e-=1.6× 10-1ºC
Note: Answer will be in two decimal places](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1ada479c-189d-4564-b08b-ebad1864080a%2Fccd0c58e-a392-4a17-a54d-a70bb6d0521e%2Fdf99eng_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the speed of a proton in (m/s) that is accelerated from rest
through an electric potential difference of 178 V.
m.-= 9.11 x 10-31kg
me+=1.66 x 10-27kg
de+ =9e-=1.6× 10-1ºC
Note: Answer will be in two decimal places
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