Calculate the speed of a proton in (m/s) that is accelerated from rest through an electric potential difference of 149 V. m-=9.11 x 10-31kg e' me+= 1.66 x 10-27kg de+=9-=1.6 x 10-19C Note: Answer will be in two decimal places

Calculate the speed of a proton in (m/s) that is accelerated from rest through an electric potential difference of 149 V. m-=9.11 x 10-31kg e' me+= 1.66 x 10-27kg de+=9-=1.6 x 10-19C Note: Answer will be in two decimal places

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter19: Electric Potential And Electric Field

Section: Chapter Questions

Problem 23PE: An electron is to be accelerated in a uniform electric field having a strength of 2.00106 V/m. (a)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

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Calculate the speed of a proton in (m/s) that is accelerated
from rest through an electric potential difference of 149 V.
m.-=9.11 x 10-31kg
me+=1.66 x 10-27kg
9e+=9-=1.6 × 10-19C
Note: Answer will be in two decimal places

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