Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous solution containing M2X1 (where X is the anion) with a supplied current of 4.98 A for 11 h, consuming 0.1145 kWh of electrical energy. Assume that the current efficiency is 93%. (Input values only with 2 decimal places

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A:

Q: A solution of nickel(II) ion (Ni2+) is electrolyzed using a current of 15.0 A (amperes) for 25.0…

A:

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Given: Current = 7.33 A Time passed = 10 hour Power = 0.2229 KWh. Current efficiency = 81 %

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A:

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Electrical energy=0.1599 kWh

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Answer: If current efficiency is 96% then effective current passed…

Q: culate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueo ent…

A:

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Electrical energy=0.1826 kWh

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Answer: Given current efficiency is 96%, therefore actual current passed…

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Given: Current = 5.72 A Time passed = 8 hour Power = 0.2293 KWh. Current efficiency = 91 %

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Answer: Since, given current efficiency is 87%, therefore actual current passed through the solution…

Q: unknown metal (M) was electrodeposited from an aqueous solution containing M2X2 (where X is the…

A:

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Given: Current = 5.72 A Time passed = 8 hour Power = 0.2293 KWh. Current efficiency = 91 %

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Given: Current = 5.56 A Time passed = 10 hour Power = 0.2196 KWh. Current efficiency = 94 %

Q: Working Backwards Tutorial. OMe HO PCI3 CI. MeO I..

A: In this reaction , reagent used is PCl3 . This reagent is specific for conversion of primary and…

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Electrical energy=0.1145 kWh

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A:

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A:

Q: An aqueous solution of nickel acetate is electrolyzed for 3 hours with a 1.3 ampere current. What…

A: We have following reaction Ni2+ +2e ---> Ni(s) moles of electrons required to form 1 mole Ni(s)=2…

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Let voltage required is V volt . And we are given 91%effeicient current = 6.82 ,so nett effective…

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Formula of energy=Vit

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Answer: Since, current efficiency given is 93%, therefore actual current passed…

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Electrical energy consumed = 0.2018 kWh.

Q: An aqueous solution of an unknown salt of molybdenum is electrolyzed by a current of 2.50 A passing…

A:

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A:

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Answer: Given current efficiency is 91%, therefore actual current passed…

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Given: Current = 6.2 A Time passed = 11 hour Power = 0.2406 KWh. Current efficiency = 96 %

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Given: Current = 6.82 A Time passed = 10 hour Power = 0.179 KWh. Current efficiency = 91 %

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A:

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Given: Current = 4.1 A Time passed = 9 hour Power = 0.2027 KWh. Current efficiency = 93 %

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Given: Current = 4.05 A Time passed = 8 hour Power = 0.2411 KWh. Current efficiency = 90 %

Q: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited from an aqueous…

A: Voltage calculated is voltage supplied and energy is assumed to be input energy or total energy…

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Given the electrical energy supplied or electrical work done, W = 0.188 kWh  time, t = 10 h Current,…

Q: ELECTROCHEMISTRY: Calculate the required voltage (V) if an unknown metal (M) was electrodeposited…

A: Given: Current = 5.05 A Time passed = 12 hour Power = 0.1734 KWh. Current efficiency = 86 %

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.