Calculate the reaction enthalpy change at 1450 K for the reaction:1/2 H2 (g) +Cl2 (g) → HCl (g)ChemicalH₂ (g)Cl2 (g)HC1 (g)AfH (298.15 K)(kJ/mol)0.000.00-92.3CRm J K-¹ mol-¹29.064 0.8363 x 10-3 T/K+20.111 x 10-7T²/K²31.695+10.143 x 10-3 T/K-40.373 x 10-7T²/K²28.165 +1.809 x 10-3 T/K + 15.464 x 10-7 T²/K²

The objective of the question is to determine the enthalpy change for the given reaction.

Calculate the reaction enthalpy change at 1450 K for the reaction: 1/2 H2 (g) + Cl2 (g) → HCl (g) Chemical H₂ (g) Cl2 (g) HCl (g) AfH (298.15 K) (kJ/mol) 0.00 0.00 -92.3 CR. JK-¹ mol-¹ 29.064 0.8363 x 10-3 T/K+20.111 x 10-7 T²/K² L 31.695 +10.143 x 10-3 T/K-40.373 x 10-7 T²/K² 28.165 +1.809 x 10-3 T/K + 15.464 x 10-7 T²/K²

Calculate the reaction enthalpy change at 1450 K for the reaction: 1/2 H2 (g) + Cl2 (g) → HCl (g) Chemical H₂ (g) Cl2 (g) HCl (g) AfH (298.15 K) (kJ/mol) 0.00 0.00 -92.3 CR. JK-¹ mol-¹ 29.064 0.8363 x 10-3 T/K+20.111 x 10-7 T²/K² L 31.695 +10.143 x 10-3 T/K-40.373 x 10-7 T²/K² 28.165 +1.809 x 10-3 T/K + 15.464 x 10-7 T²/K²

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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