Calculate the rate constant, k, for a reaction at 50.0 °C that has an activation energy of 87.9 kJ/mol and a frequency factor of 2.76 x 1011 s-. k =
Calculate the rate constant, k, for a reaction at 50.0 °C that has an activation energy of 87.9 kJ/mol and a frequency factor of 2.76 x 1011 s-. k =
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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![### Calculate the Rate Constant for a Reaction
To determine the rate constant \( k \) for a reaction at a given temperature, we can use the Arrhenius equation. This equation relates the rate constant to the temperature, activation energy, and frequency factor of the reaction.
**Problem Statement:**
Calculate the rate constant, \( k \), for a reaction at 50.0 °C that has an activation energy of 87.9 kJ/mol and a frequency factor of \( 2.76 \times 10^{11} \) s\(^{-1}\).
**Given Data:**
- Temperature, \( T \) = 50.0 °C
- Activation Energy, \( E_a \) = 87.9 kJ/mol
- Frequency Factor, \( A \) = \( 2.76 \times 10^{11} \) s\(^{-1}\)
### Step-by-Step Calculation
1. **Convert Temperature to Kelvin:**
\[
T = 50.0 + 273.15 = 323.15 \, \text{K}
\]
2. **Convert Activation Energy to Joules (J):**
Since \( 1 \, \text{kJ} = 1000 \, \text{J} \),
\[
E_a = 87.9 \times 1000 = 87900 \, \text{J/mol}
\]
3. **Use the Arrhenius Equation:**
\[
k = A e^{-\frac{E_a}{RT}}
\]
where:
- \( R \) is the gas constant, \( 8.314 \, \text{J/mol·K} \)
- \( A \) is the frequency factor
- \( E_a \) is the activation energy
- \( T \) is the temperature in Kelvin
Plugging in the values:
\[
k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\left(-\frac{87900}{8.314 \times 323.15}\right)
\]
4. **Calculate the Exponential Term:**
\[
k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0fb1b0dd-f924-4eb5-b32c-ca16550cc38a%2F54e3da9a-34cb-4b31-b1ab-9f4948adc1b1%2Fn86oi3s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Calculate the Rate Constant for a Reaction
To determine the rate constant \( k \) for a reaction at a given temperature, we can use the Arrhenius equation. This equation relates the rate constant to the temperature, activation energy, and frequency factor of the reaction.
**Problem Statement:**
Calculate the rate constant, \( k \), for a reaction at 50.0 °C that has an activation energy of 87.9 kJ/mol and a frequency factor of \( 2.76 \times 10^{11} \) s\(^{-1}\).
**Given Data:**
- Temperature, \( T \) = 50.0 °C
- Activation Energy, \( E_a \) = 87.9 kJ/mol
- Frequency Factor, \( A \) = \( 2.76 \times 10^{11} \) s\(^{-1}\)
### Step-by-Step Calculation
1. **Convert Temperature to Kelvin:**
\[
T = 50.0 + 273.15 = 323.15 \, \text{K}
\]
2. **Convert Activation Energy to Joules (J):**
Since \( 1 \, \text{kJ} = 1000 \, \text{J} \),
\[
E_a = 87.9 \times 1000 = 87900 \, \text{J/mol}
\]
3. **Use the Arrhenius Equation:**
\[
k = A e^{-\frac{E_a}{RT}}
\]
where:
- \( R \) is the gas constant, \( 8.314 \, \text{J/mol·K} \)
- \( A \) is the frequency factor
- \( E_a \) is the activation energy
- \( T \) is the temperature in Kelvin
Plugging in the values:
\[
k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\left(-\frac{87900}{8.314 \times 323.15}\right)
\]
4. **Calculate the Exponential Term:**
\[
k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\
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