Calculate the rate constant, k, for a reaction at 50.0 °C that has an activation energy of 87.9 kJ/mol and a frequency factor of 2.76 x 1011 s-. k =

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### Calculate the Rate Constant for a Reaction

To determine the rate constant \( k \) for a reaction at a given temperature, we can use the Arrhenius equation. This equation relates the rate constant to the temperature, activation energy, and frequency factor of the reaction. 

**Problem Statement:**

Calculate the rate constant, \( k \), for a reaction at 50.0 °C that has an activation energy of 87.9 kJ/mol and a frequency factor of \( 2.76 \times 10^{11} \) s\(^{-1}\).

**Given Data:**
- Temperature, \( T \) = 50.0 °C
- Activation Energy, \( E_a \) = 87.9 kJ/mol
- Frequency Factor, \( A \) = \( 2.76 \times 10^{11} \) s\(^{-1}\)

### Step-by-Step Calculation

1. **Convert Temperature to Kelvin:**
   \[
   T = 50.0 + 273.15 = 323.15 \, \text{K}
   \]

2. **Convert Activation Energy to Joules (J):**
   Since \( 1 \, \text{kJ} = 1000 \, \text{J} \),
   \[
   E_a = 87.9 \times 1000 = 87900 \, \text{J/mol}
   \]

3. **Use the Arrhenius Equation:**
   \[
   k = A e^{-\frac{E_a}{RT}}
   \]
   where:
   - \( R \) is the gas constant, \( 8.314 \, \text{J/mol·K} \)
   - \( A \) is the frequency factor
   - \( E_a \) is the activation energy
   - \( T \) is the temperature in Kelvin

   Plugging in the values:
   \[
   k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\left(-\frac{87900}{8.314 \times 323.15}\right)
   \]

4. **Calculate the Exponential Term:**
   \[
   k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\
Transcribed Image Text:### Calculate the Rate Constant for a Reaction To determine the rate constant \( k \) for a reaction at a given temperature, we can use the Arrhenius equation. This equation relates the rate constant to the temperature, activation energy, and frequency factor of the reaction. **Problem Statement:** Calculate the rate constant, \( k \), for a reaction at 50.0 °C that has an activation energy of 87.9 kJ/mol and a frequency factor of \( 2.76 \times 10^{11} \) s\(^{-1}\). **Given Data:** - Temperature, \( T \) = 50.0 °C - Activation Energy, \( E_a \) = 87.9 kJ/mol - Frequency Factor, \( A \) = \( 2.76 \times 10^{11} \) s\(^{-1}\) ### Step-by-Step Calculation 1. **Convert Temperature to Kelvin:** \[ T = 50.0 + 273.15 = 323.15 \, \text{K} \] 2. **Convert Activation Energy to Joules (J):** Since \( 1 \, \text{kJ} = 1000 \, \text{J} \), \[ E_a = 87.9 \times 1000 = 87900 \, \text{J/mol} \] 3. **Use the Arrhenius Equation:** \[ k = A e^{-\frac{E_a}{RT}} \] where: - \( R \) is the gas constant, \( 8.314 \, \text{J/mol·K} \) - \( A \) is the frequency factor - \( E_a \) is the activation energy - \( T \) is the temperature in Kelvin Plugging in the values: \[ k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\left(-\frac{87900}{8.314 \times 323.15}\right) \] 4. **Calculate the Exponential Term:** \[ k = 2.76 \times 10^{11} \, \text{s}^{-1} \cdot \exp\
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