Answered: Calculate the potential difference…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Calculate the potential difference necessary to be maintained between 2 parallel plates 5.0 mm apart in order to suspend in equilibrium a small oil drop of mass 1.31×10^–14 kg with an electric charge of –2e. (Hint: Electrostatic force balances gravity.)

A) 2006 v B) 4012 v C) none of these.

Expert Solution

Step 1

Given data

The distance between the plates is $d = 5.0 mm$

The mass of the drop is $m = 1.31 \times 10^{- 14} kg$

The charge is $q = - 2 e$

The force of gravity on the drop is

$F_{g} = m g$

here g is the acceleration due to gravity

The electric force on the drop is,

$F_{e} = q (\frac{V_{o}}{d})$

here $V_{o}$ is the necessary potential difference.

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