Calculate the physiological AG (not AG.') for the reaction: Phosphocreatine + ADP creatine + ATP Given; Phosphocreatine + H:0 creatine + Pi ADP + Pi → ATP + H;0 AG. - -43 kJ/mol AG.'-+30.5 kJ/mol at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM. (R = 8.315 JK" mol")

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Chapter1: Chemical Foundations
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answer i only

(i)
Calculate the physiological AG (not AG.') for the reaction:
Phosphocreatine + ADP creatine + ATP
Given;
Phosphocreatine + H20 → creatine + Pi
ADP + Pi → ATP + H:0
AG,' = -43 kJ/mol
AG.' =+30.5 kJ/mol
at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at
4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM.
(R= 8.315 JK' mol"')
(ii)
Calculate the free energy change at standard conditions for the following reaction:
Acetaldehyde + NADH + H* + Ethanol + NAD
The half- reactions are:
Acetaldehyde + 2H + 2e + Ethanol
NAD + 2H + 2e +
E"= - 0.20V
NADH + H-
E°"= - 0.32V
(F= 96.485 kJ/V/mol)
Transcribed Image Text:(i) Calculate the physiological AG (not AG.') for the reaction: Phosphocreatine + ADP creatine + ATP Given; Phosphocreatine + H20 → creatine + Pi ADP + Pi → ATP + H:0 AG,' = -43 kJ/mol AG.' =+30.5 kJ/mol at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM. (R= 8.315 JK' mol"') (ii) Calculate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD The half- reactions are: Acetaldehyde + 2H + 2e + Ethanol NAD + 2H + 2e + E"= - 0.20V NADH + H- E°"= - 0.32V (F= 96.485 kJ/V/mol)
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