Calculate the pH of a 0.42M CH3COOH solution, given that K(CH³COOH) = 1.8x10-5 Data: Kb x Ka = Kw = 1.00 x 10-¹4, pH = -log[H*], PH + POH = 14 pH = = ? (ans: 2 decimal places) Hint: an ICE table might be useful here Answer:
Calculate the pH of a 0.42M CH3COOH solution, given that K(CH³COOH) = 1.8x10-5 Data: Kb x Ka = Kw = 1.00 x 10-¹4, pH = -log[H*], PH + POH = 14 pH = = ? (ans: 2 decimal places) Hint: an ICE table might be useful here Answer:
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![Calculate the pH of a 0.42M CH3COOH solution, given that K(CH³COOH) = 1.8x10-5
Data: Kb x Ka = Kw = 1.00 x 10-¹4, pH = -log[H*], PH + POH = 14
pH =
= ? (ans: 2 decimal places)
Hint: an ICE table might be useful here
Answer:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f989add-2674-4ef2-9d52-3fcbf95c09c9%2F0494f6fa-936c-4ca2-838b-ff66f808556e%2F5otsqsc_processed.png&w=3840&q=75)
Transcribed Image Text:Calculate the pH of a 0.42M CH3COOH solution, given that K(CH³COOH) = 1.8x10-5
Data: Kb x Ka = Kw = 1.00 x 10-¹4, pH = -log[H*], PH + POH = 14
pH =
= ? (ans: 2 decimal places)
Hint: an ICE table might be useful here
Answer:
Expert Solution
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Step 1
Given:
Concentration of acid =0.42M
Ka of acid = 1.8 × 10-5
pH = ?
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Solved in 3 steps with 1 images
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