Calculate the pH of a 0.100 M of NaCH3COO solution. Ka of CH3COOH = 1.8 x 10-5             Ka = Kw/Kb

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Calculate the pH of a 0.100 M of NaCH3COO solution.

Ka of CH3COOH = 1.8 x 10-5             Ka = Kw/Kb

Expert Solution
Step 1

Since NaCH3COO has ion CH3COO- which is conjugate base of weak acid CH3COOH 

Hence in solution, CH3COO- will undergo hydrolysis as per the reaction 

=> CH3COO- (aq) + H2O (l) ------> CH3COOH (aq) + OH- (aq)

 

Step 2

Assuming y concentration of CH3COO- reacts as per the reaction.

Hence the concentration of products formed are 

[CH3COOH] = y = [OH- ]

And concentration of CH3COO- remaining = initial - reacted = 0.1 - y = [CH3COO- ]

 

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