Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![**Problem Statement:**
Calculate the pH and \([S^{2-}]\) in a 0.088-M \(H_2S\) solution. Assume
\[K_{a_1} = 1.0 \times 10^{-7}\]
\[K_{a_2} = 1.0 \times 10^{-19}\]
**Solution:**
\[ \text{pH} = \_\_\_\_\_ \]
\[ [S^{2-}] = \_\_\_\_\_ M \]
**Explanation:**
To solve for the pH and the concentration of sulfide ions \([S^{2-}]\) in a 0.088 M \(H_2S\) solution, we need to work with the dissociation constants \(K_{a_1}\) and \(K_{a_2}\).
1. **Initial Dissociation:** \(H_2S\) dissociates in water to form \(HS^-\) and \(H^+\).
\[H_2S \rightleftharpoons HS^- + H^+\]
The equilibrium expression for this dissociation is given by:
\[K_{a_1} = \frac{[HS^-][H^+]}{[H_2S]} = 1.0 \times 10^{-7}\]
2. **Second Dissociation:** \(HS^-\) further dissociates to form \(S^{2-}\) and \(H^+\).
\[HS^- \rightleftharpoons S^{2-} + H^+\]
The equilibrium expression for this dissociation is given by:
\[K_{a_2} = \frac{[S^{2-}][H^+]}{[HS^-]} = 1.0 \times 10^{-19}\]
Based on these expressions, we can calculate the \([H^+]\) and \([S^{2-}]\) to determine the pH and the concentration of sulfide ions (\([S^{2-}]\)) in the solution.
**Note:** To find the exact values, you may need to set up and solve the equilibrium expressions based on the given \(K_a\) values and initial concentration of \(H_2S\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5fe141b1-9817-4d6d-9b09-948fe13c457c%2F5d2e4788-de30-4501-8748-2b7059d0d87c%2F98u89j_processed.jpeg&w=3840&q=75)
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