calculate the percent yield if 1.08 g of copper is produced from 5.66 g of copper(II) sulfate and excess zinc. give answer to 3 sig figs Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s)

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calculate the percent yield if 1.08 g of copper is produced from 5.66 g of copper(II) sulfate and excess zinc. give answer to 3 sig figs

Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s)

Expert Solution
Step 1

Given reaction is 

Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s)         

Mass of CuSO4 = 5.66 g

 

Molecular weight of CuSO4 = 159.61  g/mol

Molecular weight of Cu = 63.55  g/mol

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