Calculate the number of vacancies per cubic meter in gold at 900 degrees Celsius. The energy for vacancy formation is 0.98eV/atom. The density of gold is 19.32 g/cm³ and its atomic weight is 197 g/mol. a) 3.60×102m³ b) 3.55×1023m³ c) 3.67×1024m d) 3.65×1025 m³ T=800+273 T=1173k Q₁ = 0.18 ev/atom = 1. 32 g/cm³. A =179/mol n=4 1P-32 = glam> P73 Ve 6.02 +10 Vc = 6.787023 cm³ Im² = 1000 10°cm (- Pd N= lo 6.78715 -1476464 Nr= Ne 14

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Chapter8: Molecules And Materials
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Calculate the number of vacancies per cubic meter in gold at 900 degrees Celsius. The
energy for vacancy formation is 0.98eV/atom. The density of gold is 19.32 g/cm³
and its atomic weight is 197 g/mol.
a) 3.60×102m³
b) 3.55×1023m³
c) 3.67×1024m
d) 3.65×1025 m³
T=800+273
T=1173k
Q₁ = 0.18 ev/atom
= 1. 32 g/cm³.
A =179/mol
n=4
1P-32 =
glam>
P73
Ve 6.02 +10
Vc = 6.787023 cm³
Im² = 1000 10°cm
(- Pd
N= lo
6.78715
-1476464
Nr= Ne
14
Transcribed Image Text:Calculate the number of vacancies per cubic meter in gold at 900 degrees Celsius. The energy for vacancy formation is 0.98eV/atom. The density of gold is 19.32 g/cm³ and its atomic weight is 197 g/mol. a) 3.60×102m³ b) 3.55×1023m³ c) 3.67×1024m d) 3.65×1025 m³ T=800+273 T=1173k Q₁ = 0.18 ev/atom = 1. 32 g/cm³. A =179/mol n=4 1P-32 = glam> P73 Ve 6.02 +10 Vc = 6.787023 cm³ Im² = 1000 10°cm (- Pd N= lo 6.78715 -1476464 Nr= Ne 14
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