Calculate the number of moles of aluminum and silicon required to produce 195.0 g of chromium based on the following equations: Cr₂O3+2A1→→→→2Cr +Al₂O3 2Cr₂03 +3Si 4Cr+3SiO₂ →→→

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Chapter1: Chemical Foundations
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### Question 08

Calculate the number of moles of aluminum and silicon required to produce 195.0 g of chromium based on the following equations:

\[ \text{Cr}_2\text{O}_3 + 2\text{Al} \rightarrow 2\text{Cr} + \text{Al}_2\text{O}_3 \]

\[ 2\text{Cr}_2\text{O}_3 + 3\text{Si} \rightarrow 4\text{Cr} + 3\text{SiO}_2 \]

#### 1st Attempt

##### Part 1

**[Instructor's Note]**

\[ \text{moles Al} \]

[See Periodic Table] [See Hint]

##### Part 2

**[Instructor's Note]**

\[ \text{moles Si} \]

[See Hint]

---

Here, the question prompts students to find the moles of aluminum (Al) and silicon (Si) needed to produce a specific amount of chromium (Cr) using two chemical reaction equations. The functionality of the interactive features, such as "See Periodic Table" and "See Hint", is typically provided to aid students in their calculations.
Transcribed Image Text:### Question 08 Calculate the number of moles of aluminum and silicon required to produce 195.0 g of chromium based on the following equations: \[ \text{Cr}_2\text{O}_3 + 2\text{Al} \rightarrow 2\text{Cr} + \text{Al}_2\text{O}_3 \] \[ 2\text{Cr}_2\text{O}_3 + 3\text{Si} \rightarrow 4\text{Cr} + 3\text{SiO}_2 \] #### 1st Attempt ##### Part 1 **[Instructor's Note]** \[ \text{moles Al} \] [See Periodic Table] [See Hint] ##### Part 2 **[Instructor's Note]** \[ \text{moles Si} \] [See Hint] --- Here, the question prompts students to find the moles of aluminum (Al) and silicon (Si) needed to produce a specific amount of chromium (Cr) using two chemical reaction equations. The functionality of the interactive features, such as "See Periodic Table" and "See Hint", is typically provided to aid students in their calculations.
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