Calculate the number of milliliters of 0.793 M NaOH required to precipitate all of the Fe³+ ions in 105 mL of 0.767 M Fe₂(SO4)3 solution as Fe(OH)3. The equation for the reaction is: Fe2(SO4)3(aq) + 6NaOH(aq) → 2Fe(OH)3 (s) + 3Na2SO4 (aq) Volume = mL

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases
Section16.6: Types Of Acid-base Reactions
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Calculate the number of milliliters of 0.793 M NaOH required to precipitate all of the Fe³+ ions in 105 mL of 0.767 M Fe2(SO4)3 solution as Fe(OH)3. The equation for the reaction is:
Fe2(SO4)3(aq) + 6NaOH(aq) → 2Fe(OH)3 (s) + 3Na2SO4 (aq)
Volume =
mL
Transcribed Image Text:Calculate the number of milliliters of 0.793 M NaOH required to precipitate all of the Fe³+ ions in 105 mL of 0.767 M Fe2(SO4)3 solution as Fe(OH)3. The equation for the reaction is: Fe2(SO4)3(aq) + 6NaOH(aq) → 2Fe(OH)3 (s) + 3Na2SO4 (aq) Volume = mL
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