Calculate the number of liters of NH3 that are produced when 23.32 g of LizN react with water. LigN + H20 - NH3 + 3 LIOH (Molar Mass of LigN = 34.83 g/mol and 1 mol of a gas = 22.4L) O a 15.00 L NH3 Ob 29.97 L NH3 0.03 L NH, 007L NH.

Chemistry & Chemical Reactivity
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Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
Section4.3: Percent Yield
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Calculate the number of liters of NH3 that are produced when 23.32 g of Li3N react with water. 

Li3N + H2O → NH+ 3 LiOH

(Molar Mass of Li3N = 34.83 g/mol and 1 mol of a gas = 22.4L)

Calculate the number of liters of NH3 that are produced when 23.32 g of LigN react with water.
LizN + H20 – NH3 + 3 LIOH
(Molar Mass of LigN = 34.83 g/mol and 1 mol of a gas = 22.4L)
O a
15.00 L NH3
Ob
29.97 L NH3
0.03 L NH,
O d
0.07 L NH3
Transcribed Image Text:Calculate the number of liters of NH3 that are produced when 23.32 g of LigN react with water. LizN + H20 – NH3 + 3 LIOH (Molar Mass of LigN = 34.83 g/mol and 1 mol of a gas = 22.4L) O a 15.00 L NH3 Ob 29.97 L NH3 0.03 L NH, O d 0.07 L NH3
Expert Solution
Step 1

Mass of Li3N = 23.32 gm 

Moles of Li3N = mass /molar mass of Li3

= 23.32/34.83 = 0.67

Balanced chemical reaction is 

Li3N + 3H2O => NH3 + 3LiOH

 

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