Calculate the number density of valence electrons in a certain metallic element given that the element crystallises in a BCC structure with a lattice constant of 0.415 nm, and that the element is monovalent (i.e. each atom has a single valence electrons). Assuming that the mean free path of the electrons is 1.3 nm, calculate the collision time and the conductivity of the element at 350 K, using the classical Drude model of electrical conduction. O a. Electron density = 2.80 x 1028 m 3; collision time 1.03 x 10-14 s; conductivity = 8.13 x 106 'm1 O b. Electron density = 4.56 x 1028 m-3: collision time = 2.45 x 10-14 s; conductivity = 3.88 x 106 0Im-1 O c. Electron density = 6.53 x 1026 m-3: collision time = 2.45 x 10-14 s; conductivity = 9.26 x 105 'm1 d. Electron density 1.40 x 1028 m-3; collision time 1.03 x 10-14 s; conductivity = 4.07 x 106 Q 'm

Calculate the number density of valence electrons in a certain metallic element given that the element crystallises in a BCC structure with a lattice constant of 0.415 nm, and that the element is monovalent (i.e. each atom has a single valence electrons). Assuming that the mean free path of the electrons is 1.3 nm, calculate the collision time and the conductivity of the element at 350 K, using the classical Drude model of electrical conduction. O a. Electron density = 2.80 x 1028 m 3; collision time 1.03 x 10-14 s; conductivity = 8.13 x 106 'm1 O b. Electron density = 4.56 x 1028 m-3: collision time = 2.45 x 10-14 s; conductivity = 3.88 x 106 0Im-1 O c. Electron density = 6.53 x 1026 m-3: collision time = 2.45 x 10-14 s; conductivity = 9.26 x 105 'm1 d. Electron density 1.40 x 1028 m-3; collision time 1.03 x 10-14 s; conductivity = 4.07 x 106 Q 'm

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter5: Gases

Section: Chapter Questions

Problem 146AE: One of the chemical controversies of the nineteenth century concerned the element beryllium (Be)....

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Concept explainers

Crystal Lattices and Unit Cell

Consider a crystal. The regular and repeating pattern of constituent particles is the most distinguishing feature of crystalline solids. A crystal lattice is formed when these particles are replaced with representative points. The three-dimensional arrangement of constituent particles is known as a crystal lattice. Unit cell is that the smallest portion of a space lattice which when repeated in several directions, generate the whole lattice. Unit cell is a building block of a lattice. It is the smallest unit of cell.

Question

Calculate the number density of valence electrons in a certain metallic element given that the element crystallises in a BCC
structure with a lattice constant of 0.415 nm, and that the element is monovalent (i.e. each atom has a single valence electrons).
Assuming that the mean free path of the electrons is 1.3 nm, calculate the collision time and the conductivity of the element at 350
K, using the classical Drude model of electrical conduction.
O a. Electron density = 2.80 x 1028 m-3, collision time = 1.03 x 10-14 s; conductivity = 8.13 x 106 0'm
Electron density = 4.56 x 1028 m-3; collision time = 2.45 x 10-14 s; conductivity = 3.88 x 106 Qm-
O c.
Electron density = 6.53 x 1026 m 3; collision time 2.45 x 10-14 s; conductivity 9.26 x 105'm
d. Electron density 1.40 x 1028 m-3; collision time 1.03 x 10-14 s; conductivity = 4.07 x 106 Q 'm

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