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Calculate the lattice enthalpy of AgCl (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea. CI - CI (g) Enthalpy of dissociation = 223 kJ/mol Ag (g) Enthalpy of formation = 265 kJ/mol CI (g) Electron attachment enthalpy = -369 kJ/mol Ag (g) Enthalpy of ionization = 711 kJ/mol Enthalpy of formation = -147 kJ/mol AgCl (s) kJ/mol Do you expect the magnitude (absolute value) of this to be larger or smaller than the lattice enthalpy of AgBr (s)?

Calculate the lattice enthalpy of AgCl (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea. CI - CI (g) Enthalpy of dissociation = 223 kJ/mol Ag (g) Enthalpy of formation = 265 kJ/mol CI (g) Electron attachment enthalpy = -369 kJ/mol Ag (g) Enthalpy of ionization = 711 kJ/mol Enthalpy of formation = -147 kJ/mol AgCl (s) kJ/mol Do you expect the magnitude (absolute value) of this to be larger or smaller than the lattice enthalpy of AgBr (s)?

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter12: The Solid State
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Calculate the lattice enthalpy of AgCl (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea. CI - CI (g) Enthalpy of dissociation = 223 kJ/mol Ag (g) 265 kJ/mol Cl (g) Enthalpy of formation Electron attachment enthalpy Enthalpy of ionization Enthalpy of formation = -147 kJ/mol Ag (g) 711 kJ/mol AgCl (s) = = = -369 kJ/mol kJ/mol Do you expect the magnitude (absolute value) of this to be larger or smaller than the lattice enthalpy of AgBr (s)?
Transcribed Image Text:Calculate the lattice enthalpy of AgCl (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea. CI - CI (g) Enthalpy of dissociation = 223 kJ/mol Ag (g) 265 kJ/mol Cl (g) Enthalpy of formation Electron attachment enthalpy Enthalpy of ionization Enthalpy of formation = -147 kJ/mol Ag (g) 711 kJ/mol AgCl (s) = = = -369 kJ/mol kJ/mol Do you expect the magnitude (absolute value) of this to be larger or smaller than the lattice enthalpy of AgBr (s)?
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