Calculate the minimum power of the pump which willsend the jet of water over the wall shown in Figure B.Neglect losses.EL 767.5 cm 0EL 60 mEL 55 mWS45pump30 mFIGURE B

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Answered: Calculate the minimum power of the pump…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A pump draws water at 20 liters per second from reservoir A and lifts it to reservoir B, as shown in Figure . The head loss from A to 1 is three times the velocity head in the 150-mm diameter pipe, and the head loss from 2 to B is fifteen times the velocity head in the 100-mm diameter pipe. 1. Compute the Power delivered by the pump in kw ( A. 79.07 , B. 48.10 C. 13.08 , D. 57.23) 2. Compute the Pressure head at point 1 in m. ( A. 85.96 , B. 19.74 C. 245.09 , D. 45.90) 3. Pressure head at point 2 in m. ( A. 104.51 , B. 246.67 C. 57.84 , D. 12.69)
Calculate the total pressure and the depth of the center of pressure on the inclined gate A1B shown in the figure. The width of the gate perpendicular to the plane of paper is 1 meter. (one meter)
The tank in the figure is open to the environment and divided into two compartments, connected by the flat gate C-D (2 m long), which can rotate around C. In the compartment on the left there is a level of 4.30 m of water at 20°C, which makes gate C-D remain in equilibrium (that is, Rx = 0 in D), compensating for the effect of the penstock's own weight (9000 N/m2), as well as the hydrostatic force caused by water from the compartment on the right. Under these conditions and knowing that the deposit has a width of 1 meter, calculate: a) The water level, H, in the compartment on the right, b) The reactions in the supports of the gate A-B, knowing that the gate can rotate on support A, and is simply supported in b h=4.30 m D RD=0 45° L = 2m C H A B R=1.5 m
Two water tanks are connected to each other through a mercury manometer with inclined tubes. For a given pressure difference between the two tanks Pg-PA=30 kN/m2. Which nearly gives the 0 in degrees. Water A a 26.8 cm 2a Water в Mercury а. 57 о b. 28 О с. 23 O d. 61
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9. The frame shown in Fig. P348 is supported in pivots at A and B. Each member weighs 5kN/m. Compute the horizontal reaction at A and the horizontal and vertical components of the reaction at B.
The pump in the figure B. draws water from a reservoir and discharges through 2 V2 inches hose, which terminates in a nozzle having a jet diameter of inch. The head losses are: I to 2. 5.75 ft: 2 to 3. negligible: 3 to 4. 30.61 ft. 4 to 5. 11.6 ft. Compute the required horsepower output of the pump and make a table of the heads at the five points. Q is (a) 261 gpm. (b) 361 gpm.
Water flows through a pipe at 150 L/s that changes gradually in diameter from 165 mm at point A to 473 mm 4.3 m higher than at point A and B are at point respective pressures 49.8 kPa. В. В is point A. The 72 КРа and Determine the head loss of the pipe. а. b. Determine the total energy at point B with datum at point A. Determine the total energy at point A with datum at C. point A.
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Water is flowing through a pipe of diameter 200mm with a velocity 3 m/s. Find the Reynolds no. (given v = 0.01 stoke)
Q6. A length of aluminum wire is connected to a 10.00-V power supply, and a current of 0.4212 A is measured at 23.5°C. The wire is placed in a new environment of unknown temperature where the measured current is 0.3818 A. What is the unknown temperature? (ai=0.00429(C°)").
ELEV. = 130m B L = 1000m D = 200mm f = 0.023 L= 1500m L = 300m D = 250mm ELEV.= 40m D = 300mm f = 0.02 f = 0.018 Q = 0.14 m3/s ELEV. = 10m 3 A Determine the power (in horsepower) delivered by the pump to the water system shown above,

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Calculate the minimum power of the pump which will send the jet of water over the wall shown in Figure B. Neglect losses. EL 76 7.5 cm Ø EL 60 m EL 55m WS 45 pump 30 m