Calculate the median of the following distribution: CLASS FREQUENCY 10- 19 8 20-29 16 30-39 12 40-49 4 TOTAL 40

Q: (-5-20-100 to

A:

Q: V-539 7. V11

A: To Determine:  Simplify

Q: 4y-12=0

A: 4y = 12 y = 3

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: Todt 5(-37+4)

A: Given,   ∫  -3t+410dt

Q: 1 +1

A: Given  1+1=

Q: -3w+5=23

A:

Q: (-3)² ÷ 3 • (5 - 10 + -8)

A:

Q: (-12)+7

A: To simplify any expression involving numbers we need to use the BODMAS rule which specifies the…

Q: 15+c=-12

A:

Q: -4d = -64

A: Given  -4d=-64

Q: -5 -2 1

A:

Q: w2+7w+12=0

A: w2+7w+12=0 Solve by factoring

Q: 7k = 91

A: We will find the value of k in the following step.

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: 2+36=38

A: Given 2+ 36 = 38  Yes the given statement is true .

Q: a1 13x +36% D

A:

Q: 1. (3, x) 2. (3x + 3, y) 3. (y, cos x) 4. (x + y, x – Y)

A: using online vector field graphing we get 1-A 2-C

Q: -3(4x-5)-6=18

A: Given: −34x−5−6=18 To determine: The value of x.

Q: z? - 34z + 818 = 0

A:

Q: (-3b)(-4)

A: To evaluate(-3b)(-4)

Q: - 6 = r-6. 3C

A: The given expression is: x-6=x-6

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.