Calculate the mean (expected value) for the discrete probability distribution shown here( answer 2 decimal places)

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Calculate the mean (expected value) for the discrete probability distribution shown here( answer 2 decimal places)
The image displays a probability distribution table for a discrete random variable \( x \). The table provides the probability \( P(x) \) for each corresponding value of \( x \). Below is a transcription of the table:

| \( x \)  | -3 | 5  | 7  | 11 | 13 |
|----------|----|----|----|----|----|
| \( P(x) \) | 0.08 | 0.2 | 0.32 | 0.35 | 0.05 |

In this table:
- The value \( x = -3 \) has a probability of 0.08.
- The value \( x = 5 \) has a probability of 0.2.
- The value \( x = 7 \) has a probability of 0.32.
- The value \( x = 11 \) has a probability of 0.35.
- The value \( x = 13 \) has a probability of 0.05.

These probabilities must sum to 1 if this distribution is valid: \( 0.08 + 0.2 + 0.32 + 0.35 + 0.05 = 1 \).

This table helps us understand the likelihood of each outcome occurring within a defined sample space.
Transcribed Image Text:The image displays a probability distribution table for a discrete random variable \( x \). The table provides the probability \( P(x) \) for each corresponding value of \( x \). Below is a transcription of the table: | \( x \) | -3 | 5 | 7 | 11 | 13 | |----------|----|----|----|----|----| | \( P(x) \) | 0.08 | 0.2 | 0.32 | 0.35 | 0.05 | In this table: - The value \( x = -3 \) has a probability of 0.08. - The value \( x = 5 \) has a probability of 0.2. - The value \( x = 7 \) has a probability of 0.32. - The value \( x = 11 \) has a probability of 0.35. - The value \( x = 13 \) has a probability of 0.05. These probabilities must sum to 1 if this distribution is valid: \( 0.08 + 0.2 + 0.32 + 0.35 + 0.05 = 1 \). This table helps us understand the likelihood of each outcome occurring within a defined sample space.
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