Calculate the mass of precipitate (in g) produced when 75 mL of 6.00 mol/L sodium hydroxide solution is reacted with excess aluminium nitrate solution. AI(NO3)₂(aq) +3 NaOH(aq) → Al(OH)₂(s) + 3 NaNO3(aq) Do not show your work in the space provided. Only record your final answer with the correct number of significant digits and the proper units.
Calculate the mass of precipitate (in g) produced when 75 mL of 6.00 mol/L sodium hydroxide solution is reacted with excess aluminium nitrate solution. AI(NO3)₂(aq) +3 NaOH(aq) → Al(OH)₂(s) + 3 NaNO3(aq) Do not show your work in the space provided. Only record your final answer with the correct number of significant digits and the proper units.
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![Calculate the mass of precipitate (in g)
produced when 75 mL of 6.00 mol/L sodium
hydroxide solution is reacted with excess
aluminium nitrate solution.
AI(NO₂)₂(aq) +3 NaOH(aq) Al(OH)3(s) + 3 NaNO₂(aq)
Do not show your work in the space provided.
Only record your final answer with the correct
number of significant digits and the proper
units.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d6e75ac-cc8b-4deb-aa61-eab028f87760%2F27e6cbd2-7357-456a-a146-0b965e8dc4bf%2Favpgo6z_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate the mass of precipitate (in g)
produced when 75 mL of 6.00 mol/L sodium
hydroxide solution is reacted with excess
aluminium nitrate solution.
AI(NO₂)₂(aq) +3 NaOH(aq) Al(OH)3(s) + 3 NaNO₂(aq)
Do not show your work in the space provided.
Only record your final answer with the correct
number of significant digits and the proper
units.
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