**Calculating the Magnitude of the Normal Force**The normal force is the force exerted by a surface to support the weight of an object resting on it. In this exercise, we will calculate the magnitude of the normal force on a \(17.7 \, \text{kg}\) block in various scenarios. Enter your answers in Newtons (N).**(a)** The block is resting on a level surface.- Incorrect response indicator: ✗- Answer box to enter the normal force in N.**(b)** The block is resting on a surface tilted up at a \(40.8^\circ\) angle with respect to the horizontal.- Answer box to enter the normal force in N.**(c)** The block is resting on the floor of an elevator that is accelerating downward at \(3.28 \, \text{m/s}^2\).- Answer box to enter the normal force in N.**(d)** The block is on a level surface, and a force of \(145 \, \text{N}\) is exerted on it at an angle of \(40.8^\circ\) above the horizontal.- Answer box to enter the normal force in N.For each scenario, consider the forces acting on the block and use the appropriate equations to calculate the normal force.

Given: The mass of the block is 17.7 kg. Calculation: Part (a): The free-body diagram is given below. Here, N is the normal force, m is the mas so object and g is the acceleration due to gravity. The normal force is given as N. N=mg=17.7 kg9.8 m/s2=173.46 N Thus, the normal force is 173.46 N. Part (b): The free-body diagram is given below. Here, N is the normal force, m is the mas so object and g is the acceleration due to gravity. The normal force is given as N from the above free-body diagram. N=mgcos40.8°=17.7 kg9.8 m/s2cos40.8°=131.308 N Thus, the normal force is 131.308 N. Part (c): The free-body diagram is given below. Here, the pseudo force experienced by the object will be vertically upward because motion of elevator if vertically downward. Here, N is the normal force, a is the acceleration of the elevator, m is the mas so object and g is the acceleration due to gravity. The normal force is given as N from the above free-body diagram. N=mg-ma=17.7 kg9.8 m/s2-17.7 kg3.28 m/s2=115.404 N Thus, the normal force is 115.404 N.

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Calculate the magnitude of the normal force on a 17.7 kg block in the following circumstances. (Enter your answers in N.) HINT (a) The block is resting on a level surface. X N (b) The block is resting on a surface tilted up at a 40.8° angle with respect to the horizontal. (c) The block is resting on the floor of an elevator that is accelerating downward at 3.28 m/s. N

Calculate the magnitude of the normal force on a 17.7 kg block in the following circumstances. (Enter your answers in N.) HINT (a) The block is resting on a level surface. X N (b) The block is resting on a surface tilted up at a 40.8° angle with respect to the horizontal. (c) The block is resting on the floor of an elevator that is accelerating downward at 3.28 m/s. N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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