**Problem Statement:**2. Calculate the magnitude and direction of the force felt on the wire below. Assume the magnetic field has a strength of 0.25 T.**Diagram Description:**- The diagram shows a straight wire with a current flowing to the right, denoted by "2 A."- There is a rectangular region around the wire with "x" marks, indicating a magnetic field directed into the page.- The length of the wire within the magnetic field is specified as "20 cm."**Analysis:**To solve the problem, we can use the formula for the magnetic force on a current-carrying wire:\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]Where:- \( F \) is the magnetic force,- \( I \) is the current (2 A),- \( L \) is the length of the wire within the magnetic field (20 cm or 0.2 m),- \( B \) is the magnetic field strength (0.25 T),- \( \theta \) is the angle between the current direction and the magnetic field. In this case, since the field is perpendicular, \( \theta = 90^\circ \) and \(\sin(90^\circ) = 1\).**Conclusion:**Plugging the values into the formula gives:\[ F = 2 \, \text{A} \cdot 0.2 \, \text{m} \cdot 0.25 \, \text{T} \cdot 1 = 0.1 \, \text{N} \]The direction of the force can be determined using the right-hand rule. With the current directed to the right and the magnetic field into the page, the force will be directed upward.

Solution:Given:B = magnetic field (going into the page) = 0.25 TL = length of wire = 20 cm = 0.20 mI…

Answered: Calculate the magnitude and direction…

Calculate the magnitude and direction of the force felt on the wire below. Assume the mag- netic field has a strength of 0.25 T. X X 20 cm X X X X X X 2 A

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Problem Statement:**

2. Calculate the magnitude and direction of the force felt on the wire below. Assume the magnetic field has a strength of 0.25 T.

**Diagram Description:**

- The diagram shows a straight wire with a current flowing to the right, denoted by "2 A."
- There is a rectangular region around the wire with "x" marks, indicating a magnetic field directed into the page.
- The length of the wire within the magnetic field is specified as "20 cm."

**Analysis:**

To solve the problem, we can use the formula for the magnetic force on a current-carrying wire:
\[ F = I \cdot L \cdot B \cdot \sin(\theta) \]

Where:
- \( F \) is the magnetic force,
- \( I \) is the current (2 A),
- \( L \) is the length of the wire within the magnetic field (20 cm or 0.2 m),
- \( B \) is the magnetic field strength (0.25 T),
- \( \theta \) is the angle between the current direction and the magnetic field. In this case, since the field is perpendicular, \( \theta = 90^\circ \) and \(\sin(90^\circ) = 1\).

**Conclusion:**

Plugging the values into the formula gives:
\[ F = 2 \, \text{A} \cdot 0.2 \, \text{m} \cdot 0.25 \, \text{T} \cdot 1 = 0.1 \, \text{N} \]

The direction of the force can be determined using the right-hand rule. With the current directed to the right and the magnetic field into the page, the force will be directed upward.

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