Calculate the lattice enthalpy of InI (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea. II (g) Enthalpy of dissociation = 131 kJ/mol In (g) Enthalpy of formation = 223 kJ/mol I (g) Electron attachment enthalpy = -315 kJ/mol In (g) Enthalpy of ionization = 538 kJ/mol InI (s) Enthalpy of formation = -136 kJ/mol kJ/mol Do you expect the magnitude (absolute value) of this to be larger or smaller than the lattice enthalpy of InCl (s)?

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Calculate the lattice enthalpy of InI (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea.

- I - I (g) Enthalpy of dissociation = 131 kJ/mol
- In (g) Enthalpy of formation = 223 kJ/mol
- I (g) Electron attachment enthalpy = -315 kJ/mol
- In (g) Enthalpy of ionization = 538 kJ/mol
- InI (s) Enthalpy of formation = -136 kJ/mol

[Blank input box] kJ/mol

Do you expect the magnitude (absolute value) of this to be larger or smaller than the lattice enthalpy of InCl (s)?

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Transcribed Image Text:Calculate the lattice enthalpy of InI (s) using the following thermodynamic data. Note that the data given has been perturbed, so looking up the answer is probably not a good idea. - I - I (g) Enthalpy of dissociation = 131 kJ/mol - In (g) Enthalpy of formation = 223 kJ/mol - I (g) Electron attachment enthalpy = -315 kJ/mol - In (g) Enthalpy of ionization = 538 kJ/mol - InI (s) Enthalpy of formation = -136 kJ/mol [Blank input box] kJ/mol Do you expect the magnitude (absolute value) of this to be larger or smaller than the lattice enthalpy of InCl (s)? [Dropdown menu]
Expert Solution
Step 1

First the given data 

II (g) Enthalpy of dissociation = 131 kJ/mol

In (g) Enthalpy of formation = 223 kJ/mol

I (g) Electron attachment enthalpy = -315 kJ/mol

In (g) Enthalpy of ionization = 538 kJ/mol

InI (s) Enthalpy of formation = -136 kJ/mol

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