Calculate the ideal frequency to detect a surface defect using a Rayleigh wave.
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- In the process of performing an analysis, you determine that you need to improve the precision by limiting the error in the absorbance to 9.400 x 10%. You attempt to achieve this by reducing the amount of stray light that reaches the detector. What is the maximum amount of stray light that can reach the detector that will limit the error in the absorbance to 9.400 x 10 for a true absorbance of 1.0000000? s= 222 x10-5 IncorrectYoung's experimental setup can be used to monitor the width of the lead wires in transistors. The cables are placed in a narrow opening as shown in the figure. The opening is illuminated with highly coherent light. The position of the tenth maximum is measured on a screen located at 0.5m. The expected diameter of the wires is 0.100±0.005 mm. (a) What is the maximum deviation that the position of the tenth maximum can have so that the cable has an acceptable diameter? What would happen if the first maximum was used as the criterion, would the decision be easier or more difficult?h) The difference in arrival time between wave-packets with centre frequencies of ω1 and ω2 is Δt. What is DM in terms of Δt ?
- Quartz is a uniaxial birefringent material with refractive indices no=1.5534 and ne=1.5443. It is desired to make a quarter-wave plate of quartz for use with a Sodium laser of wavelength λ0=589 nm. Calculate the minimum thickness of the plate.Give your answer in micrometers to 1 d.p.A step-index fiber of radius a = 20 μm and refractive indices ?1 = 1.47 and?2 = 1.46 operates at ?0 = 1.55 μm . Using the quasi-plane wave theory andconsidering only guided modes with azimuthal index l = 1:(a) Determine the smallest and largest propagation constants.(b) For the mode with the smallest propagation constant, determine the radii of the cylindrical shell within which the wave is confined, and the components of the wavevector k at r = 5 μm.If the wavelength l of the Xrays is too large relative to the spacing of planes in the crystal, no Bragg diffraction will be seen because sin u would be larger than 1 in the Bragg equation, even for n 5 1. Calculate the longest wavelength of Xrays that can give Bragg diffraction from a set of planes separated by 4.20 Å.