Calculate the heat change (q) in J when 4.228 grams of water is cooled from 4.797 ºC to -2.699 ºC.

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Calculate the heat change (q) in J when 4.228 grams of water is cooled from 4.797 ºC to -2.699 ºC.

Expert Solution
Step 1

Given data

*The mass of the water is m = 4.228 g

*The initial temperature is Ti = 4.797 0C = (273.15 + 4.797) K = 277.947 K

*The final temperature is Tf = -2.699 0C = (273.15 -2.699) K = 270.451 K

 

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