Calculate the Gibbs free energy (in kJ) at 25 degrees C of the following reaction using the data in the table. 4A+2B + 3C 4D + 4E AHr (kJ/mol) A 70.34 B -5.12 C 56.20 D 48.83 E -11.18 s°U/mol/K) 107.32 32.05 175.47 82.34 40.10 Report your answer to two decimal places
Calculate the Gibbs free energy (in kJ) at 25 degrees C of the following reaction using the data in the table. 4A+2B + 3C 4D + 4E AHr (kJ/mol) A 70.34 B -5.12 C 56.20 D 48.83 E -11.18 s°U/mol/K) 107.32 32.05 175.47 82.34 40.10 Report your answer to two decimal places
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Calculate the Gibbs free energy (in kJ) at 25 degrees C of the following reaction
using the data in the table.
4A+2B+ 3C - 4D + 4E
AHf (kJ/mol)
A 70.34
B-5.12
C 56.20
D 48.83
E-11.18
s°U/mol/K)
107.32
32.05
175.47
82.34
40.10
Report your answer to two decimal places
Expert Solution
Step 1
For a general reaction
aA + bB → cc + dD
Entropyb change
∆S°rxn =( Σv S°f )product - ( Σ vS°f )reactant
∆S°rxn = [c (S°f )c + d (S°f )d] - [a(S°f )a + b(S°f )b]
enthalpy change
∆H°rxn =( Σv ∆H°f )product - ( Σ v∆H°f )reactant
∆H°rxn = [c (∆H°f )c + d (∆H°f )d] - [a(∆H°f )a + b(∆H°f )b]
gibbs free enegy change
∆G°rxn = ∆H°rxn -T ∆S°rxn
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