Calculate the force in member IJ. 15 KN 10 KN 10 KN 20 KN A В E 5.0 m 4 @ 3.0 m = 12.0 m

Q: Draw the sectional front view (front section) and draw the orthographic projection (sideand top…

A: Asked: To draw the orthographic projection views of the given object.   The orthographic projection…

Q: Compute Ix for the region shown. y 2 18 2-5--5- -2 -8 8. Dimensions in inches

A: The area is divided into the standard areas as shown below.

Q: 17. COMPLETE THE FOLLOWING INSERT CODE IN INCHES: MG 43 18. COMPLETE THE FOLLOWING INSERT CODE IN…

A: 17. It is made up of  CNMG432       1/2" inner circle , 1/32" corner circle and 80°  Diamond woth 0°…

Q: Find the centroid of the following cross-sections and planes.

A: Centrodal distanceX = 5.333 inY = 5.667 inExplanation:Step 1:Step 2:

Q: 15.16 Refer to Figure 15.52. Using Michalowski's solution given in Figure 15.25 ('> 0). determine…

A: The kinematic approach of limit analysis is applied to the rigid rotational collapse mechanism by…

Q: XXXX W₂ W₁ Which of the following most nearly gives the external degree of indeterminacy? 2 4 O 1

A:

Q: Determine how far is the centroid of the given cross section above the base. 6-504 2-50" 9.0" 6.5"…

A:

Q: Assignm R= Station 18+26 18+00 17+00 16+00 15+68 3: For Arc 0 Deflection Angle (DMS) 0°0'0" Chord…

A: Horizontal Curve :  In order to transition between two tangent strips of road, a horizontal curve is…

Q: Arc command and its abbreviation is A character is the only command can be used to draw an arc in…

A: It is required to state whether true or false statement.

Q: 65 degree 6' - 17 degree 54'

A: 1 degree = 60' 65 degree 6' = 64 degree 66'

Q: show the (c)

A:

Q: What are the commonly available switch actions?

A: Commonly available switch actions? ON-OFF, SPST. SPST = Single Pole, Single Throw.  (ON)-OFF,…

Q: Figure 2. Inside perimeter Outside perimeter Centreline

A: Inside perimeter :Length×2+Breadth×2+2×2'+3'24'3''×2+12'×2+2×2'+3'=79'6''

Q: If Ax B = = A.B then the angle between A and B will be %3D a) п b) π/2 ) π/3 TE e) None of the above…

A: To find angle between A and B

Q: Explain why wx = 2/3(9-x)

A: Given:Required:To explain loading intensity for 6<x<9

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.